Answer:
uh... you forgot to add the image...
ask again with a screenshot/picture next time...
Answer:
No. 2/3 of the space to Grano and 1/3 of the space to Wheatie.
Step-by-step explanation:
Allocating about 57% to Wheatie and 43% to Grano, means to allocate 60(.57)=34.2 ft2 of Wheatie and 60(.43)=25.8 ft2 of Grano. In that case there would be 34.2/.4=85.5≈85 boxes of Wheatie and 25.8/.2=129 boxes of Grano. The total profit would be 129(1)+85(1.35)=$243.75
Best option:
200 Granos boxes and 50 Wheaties boxes on the shelf.
200(.2)=40ft^2 will allocate Granos boxes
50(.4)=20ft^2 will allocate Wheaties boxes.
This means that 40/60=2/3=66.6% of the space will allocate Granos boxes and 20/60=1/3=33.3% of the space will allocate Wheaties boxes.
The total profit would be 200(1)+50(1.35)=$267.5
EXTRA:
This is a optimization problem.
Let X1 be the number of Granos boxes
Let X2 be the number of Wheaties boxes
Objective:
Max Z=1(X1)+1.35(X2)
Subjecto to
0.2(X1)+0.4(X2)<=60,
X1<=200,
X2<=120,
X1,X2>=0.
You can solve it using the simplex method. Check the image for more details.
1. Match to B
2. Match to A
3. Match to D
4. Prime
Hope it helps!
Answer:
1250 different committees can be formed
Step-by-step explanation:
We are told that the club has 5 men and 6 women.
Now we want to choose number of men between 1 and 3 with both inclusive and number of women between 2 and 4 with both inclusive.
We'll use the combination formula;
C(n, r) = n! / [r! (n - r)!]
Where, n = population and r = picks
Thus, we'll multiply the results of the women and men together. And so we have:this gives us ;
(5C1 + 5C2 + 5C3) * (6C2 + 6C3 + 6C4) = (5 + 10 + 10) * (15 + 20 + 15) = 25 * 50 = 1250 ways