Answer:
The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.
Step-by-step explanation:
We are in posession of the sample's standard deviation, so we use the student's t-distribution to find the confidence interval.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 16 - 1 = 15
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 35 degrees of freedom(y-axis) and a confidence level of
). So we have T = 2.9467
The margin of error is:
M = T*s = 2.9467*0.058 = 0.171
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 1.053 - 0.171 = 0.882kg
The upper end of the interval is the sample mean added to M. So it is 1.053 + 0.171 = 1.224 kg.
The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.
The answer is A, not sure about the expression though. Sorry
A: From the graph, car B was traveling faster.
Because the line of car B is more steep than the line of car A.
B:
The lines cross at (2,80), this means that the two cars were traveling at the same distance (80 miles) at the same time (2 hours).
C:
Since the line passes through the points (0,0) and (2,80)
So the unit rate or slope is 40 mph.
The distance which car A traveled in the first four hours = 4x40= 160 mph
Hello.
The asnwer is ASA -
If two angles and the included side are equal to two angles and the included side of another triangle.
Have a nice day