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Colt1911 [192]
2 years ago
11

Genes are sections of DNA that code for a particular trait. Genes are?​

Mathematics
1 answer:
Black_prince [1.1K]2 years ago
6 0

Answer:

Genes are DNA transferred to off spring by parents

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This should be easy for you <br> Please help me
Alik [6]

Explanation:

a. The line joining the midpoints of the parallel bases is perpendicular to both of them. It is the line of symmetry for the trapezoid. This means the angles and sides on one side of that line of symmetry are congruent to the corresponding angles and sides on the other side of the line. The diagonals are the same length.

__

b. We observe that adjacent pairs of points have the same x-coordinate, so are on vertical lines, which have undefined slope. KN is a segment of the line x=1; LM is a segment of the line x=3. If the trapezoid is isosceles, the midpoints of these segments will be on a horizontal line. The midpoint of KN is at y=(3-2)/2 = 1/2. The midpoint of LM is at y=(1+0)/2 = 1/2. These points are on the same horizontal line, so the trapezoid <em>is isosceles</em>.

__

c. We observed in part (b) that the parallel sides are KN and LM. The coordinate difference between K and L is (1, 3) -(3, 1) = (-2, 2). That is, segment KL is the hypotenuse of an isosceles right triangle with side lengths 2, so the lengths of KL and MN are both 2√2.

_____

For part (c), we used the shortcut that the hypotenuse of an isosceles right triangle is √2 times the leg length.

7 0
3 years ago
What’s the distance between (-3,-5) and (-2,-4)
joja [24]

Answer:

2.82843

Step-by-step explanation:

it was what i got

3 0
3 years ago
Read 2 more answers
Log, 7 1/2<br> Solve in exponential form
shutvik [7]
What is the log for?
6 0
2 years ago
Read 2 more answers
Express answer in exact form.
Kruka [31]
We know that
<span>the regular hexagon can be divided into 6 equilateral triangles
</span>
area of one equilateral triangle=s²*√3/4
for s=3 in
area of one equilateral triangle=9*√3/4 in²

area of a circle=pi*r²

in this problem the radius is equal to the side of a regular hexagon
r=3 in
area of the circle=pi*3²-----> 9*pi in²
we divide that area into 6 equal parts------> 9*pi/6----> 3*pi/2 in²

the area of a segment formed by a side of the hexagon and the circle is equal to <span>1/6 of the area of ​​the circle minus the area of ​​1 equilateral triangle
</span>so
 [ (3/2)*pi in²-(9/4)*√3 in²]

the answer is
 [ (3/2)*pi in²-(9/4)*√3 in²]

6 0
3 years ago
in a class there are 115 students going on a field trip 2/5 are bringing a notebook on the field trip how many students are brin
xxMikexx [17]

Answer:

46

Step-by-step explanation:

(2/5)*115

230/5

46 students

4 0
2 years ago
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