All categories

3 years ago

Which of the following occupies a volume? solids liquids gases all of the above

Chemistry

2 answers:

nataly862011 [7]3 years ago

7 0

Solids occupy a volume

nignag [31]3 years ago

7 0

A liquid has a definite volume, but not a definite shape. In a liquid, the particles move in random directions but are sufficiently attracted to each other to maintain a definite volume. Gas does not have definite shape or volume. In a gas the particle are far apart which have little attraction to each other and move at high rates of speeds taking shape and volume of their container. Hope this helps

You might be interested in

How many kilograms are in 6.983 moles of baking soda (NaCHO3)?

nasty-shy [4]

It should be about 0.586620881 kilograms

6 0

3 years ago

(5.625 + 8.15) x 2.34 + 3.2

dalvyx [7]

The answer is 35.4335

Hope this helped! (Plz mark me brainliest!)

3 0

3 years ago

Read 2 more answers

What happens to particles at absolute zero? *

Sedbober [7]

They are barley moving

4 0

3 years ago

Read 2 more answers

PLEASE HELP DUE IN 1 HOUR

NARA [144]

Answer:

All the carbon will combust with atmospheric oxygen to form carbon dioxide. This means that the charcoal present will become consumed to form colorless carbon dioxide gas.

Explanation:

8 0

3 years ago

The concentrated sulfuric acid we use in the laboratory is 98.0% sulfuric acid by weight. Calculate the molality and molarity of

timama [110]

Answer : The molarity and molality of the solution is, 18.29 mole/L and 499.59 mole/Kg respectively.

Solution : Given,

Density of solution = $1.83g/cm^3=1.83g/ml$

Molar mass of sulfuric acid (solute) = 98.079 g/mole

98.0 % sulfuric acid by mass means that 98.0 gram of sulfuric acid is present in 100 g of solution.

Mass of sulfuric acid (solute) = 98.0 g

Mass of solution = 100 g

Mass of solvent = Mass of solution - Mass of solute = 100 - 98.0 = 2 g

First we have to calculate the volume of solution.

$\text{Volume of solution}=\frac{\text{Mass of solution}}{\text{Density of solution}}=\frac{100g}{1.83g/ml}=54.64ml$

Now we have to calculate the molarity of solution.

$Molarity=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{volume of solution}}=\frac{98.0g\times 1000}{98.079g/mole\times 54.64ml}=18.29mole/L$

Now we have to calculate the molality of the solution.

$Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent}}=\frac{98.0g\times 1000}{98.079g/mole\times 2g}=499.59mole/Kg$

Therefore, the molarity and molality of the solution is, 18.29 mole/L and 499.59 mole/Kg respectively.

7 0

3 years ago