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andreyandreev [35.5K]
3 years ago
13

Question 14 of 17

Chemistry
1 answer:
artcher [175]3 years ago
4 0

Since Lutetium-177 is a beta and gamma emitter, the daughter nuclide produced from the decay of this radioisotope is 177Hf.

Beta emission of a radioisotope yields a  daughter nuclide whose amass number is the same as that of its parent nucleus but its atomic number is greater is greater than that of the parent nucleus by 1 unit.

Also, gamma emission does not lead to any change in the mass number of atomic number of the daughter nucleus produced.

Hence, the stable daughter nuclide, 177Hf is produced.

Learn more: brainly.com/question/1770619

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The following transition occurs at a molecular level for a substance. What transition corresponds to this change in microscopic
olchik [2.2K]

Answer:

D. Freezing

Explanation:

Please mark brainliest and have a great day!

5 0
3 years ago
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Gas chromatography can be useful in determining what about paint?
dexar [7]
Gas chromatography is a type of <span>chromatography that is usually used in analytic chemistry in order to analyze and separate the compounds that can be vaporized without decomposition.

Based on this:
</span><span>Gas chromatography can be useful in determining the chemical composition of paint.</span>
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What causes the ocean tides to change from high tide to low tide?
nikdorinn [45]
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6 0
3 years ago
635 mL of a gas is at a pressure of 8.00 atm. What is the volume of the gas at standard pressure (STP)?
Sveta_85 [38]

The new volume at standard temperature and pressure is 5.08 L.

Explanation:

As per the kinetic theory of gases, the volume occupied by gas molecules will be inversely proportional to the pressure of the gas molecules. This is termed as Boyle's law.

So, pressure∝\frac{1}{volume}

Thus, if two pressure and two volumes are given then,

P_{1} V_{1} = P_{2} V_{2}\\

Now, we known the values of P₁ = 8 atm, V₁ = 635 mL, P₂ = 1 atm and V₂ we have to determine. We are considering P₂ = 1 atm, because we have to determine V₂ at standard temperature and pressure. And standard pressure is 1 atm.

8*635*10^{-3}  = 1 *V{2} \\\\V_{2} = \frac{8*635*10^{-3} }{1} =   5.08 L

Thus, the new volume at standard temperature and pressure is 5.08 L.

5 0
3 years ago
CAN SOMEONE PLEASE CHECK MY ANSER PLASE
Leokris [45]
1.True
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2 years ago
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