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andreyandreev [35.5K]
3 years ago
13

Question 14 of 17

Chemistry
1 answer:
artcher [175]3 years ago
4 0

Since Lutetium-177 is a beta and gamma emitter, the daughter nuclide produced from the decay of this radioisotope is 177Hf.

Beta emission of a radioisotope yields a  daughter nuclide whose amass number is the same as that of its parent nucleus but its atomic number is greater is greater than that of the parent nucleus by 1 unit.

Also, gamma emission does not lead to any change in the mass number of atomic number of the daughter nucleus produced.

Hence, the stable daughter nuclide, 177Hf is produced.

Learn more: brainly.com/question/1770619

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What is function of phylloclade
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In some plants such as Cactuses, the stem is flattened and green and carries out the function of the leaf. Such a stem, adapted for the manufacture of food is called phylloclade. The leaves here are reduced or modified into spines to lessen the transpiring surface.

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QUESTION 20 Which of the following is a producer? oak tree raccoon cockroach human
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Answer:

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8 0
4 years ago
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An aqueous solution is analyzed and found to contain potassium ions and sulfite ions. write the equation for the dissolution of
enot [183]
1) T<span>he dissolution of the salt potassium sulfite:
K</span>₂SO₃(aq) → 2K⁺(aq) + SO₃²⁻(aq).
Potassium has +1 charge because it lost one electron to accomplish stabile electron configuration of noble gas argon.
2) From dissolution reaction: n(K⁺) : n(SO₃²⁻) = 2 : 1.
n(K⁺) = 0.700 mol.
0.700 mol : n(SO₃²⁻) = 2 : 1.
n(SO₃²⁻) = 0.700 mol ÷ 2.
n(SO₃²⁻) = 0.350 mol; amount of sulfite anions.
7 0
3 years ago
Which statement correctly describes a covalent bond?  The valence electrons are joined in a shell around the atoms. The valence
Vedmedyk [2.9K]
The valence electrons are shared between the atoms
4 0
4 years ago
A 0.15 mol sample of H2S is placed in a 10 L reaction vessel and heated to 1132◦C. At equilibrium, 0.03 mol H2is present. Calcul
Angelina_Jolie [31]

Answer: The value of the equilibrium constant is 0.00009.

Explanation:

Initial moles of  H_2S = 0.15 mole

Volume of container = 10 L

Initial concentration of H_2S=\frac{moles}{volume}=\frac{0.15moles}{10L}=0.015M  

Moles of H_2 at equilibrium= 0.03 mole

equilibrium concentration of H_2=\frac{moles}{volume}=\frac{0.03moles}{10L}=0.003M [/tex]

The given balanced equilibrium reaction is,

                            2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)

Initial conc.           0.015 M                     0     0

 At eqm. conc.    (0.015-2x) M           (2x) M   (x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[H_2]^2\times [S_2]}{[H_2S]^2}

K_c=\frac{(2x)^2\times x}{(0.015-2x)^2}

we are given : 2x= 0.003 M

x= 0.0015 M

Now put all the given values in this expression, we get :

K_c=\frac{(0.003)^2\times 0.0015}{(0.015-0.003)^2}

K_c=0.00009

Thus the value of the equilibrium constant is 0.00009.

8 0
3 years ago
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