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3 years ago

8

What is the effect of day lenght in plant growth? dependent and independent

1 answer:

Natali5045456 [20]3 years ago

5 0

Plants use energy from the Sun to trigger photosynthesis carbon dioxide pulled from the air and water drawn from the roots is converted to sugar to be used wright away or to be stored the longer the day the more food can be produced

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Determine the pH of a 5x10^-4 M solution of Ca(OH)2

miss Akunina [59]

Ca(OH)₂ ==> Ca²⁺ + 2 OH<span>-

Ca(OH)</span>₂ is <span>strong Bases</span><span>

</span>Therefore, the [OH-] equals 5 x 10⁻⁴ M. For every Ca(OH)₂ you produce 2 OH⁻<span>.
</span>
pOH = - log[ OH⁻]

pOH = - log [ <span>5 x 10⁻⁴ ]

pOH = 3.30

pH + pOH = 14

pH + 3.30 = 14

pH = 14 - 3.30

pH = 10.7

hope this helps!</span>

5 0

3 years ago

HELP ME ASAP<br> !!!!!!!!!!

Cloud [144]

Answer:

the yellow one

Explanation:

it includes direction

3 0

2 years ago

Read 2 more answers

At a given temperature the vapor pressure of pure liquid benzene and toluene are 745 torr and 290 torr, respectively. A solution

IRISSAK [1]

Answer:

Vapour pressure of benzene over the solution is 253 torr

Explanation:

According to Raoult's law for a mixture of two liquid component A and B-

vapour pressure of a component (A) in solution = $x_{A}\times P_{A}^{0}$

vapour pressure of a component (B) in solution = $x_{B}\times P_{B}^{0}$

Where $x_{A},x_{B}$ are mole fraction of component A and B in solution respectively

$P_{A}^{0},P_{B}^{0}$ are vapour pressure of pure A and pure B respectively

Here mole fraction of benzene in solution is 0.340 and vapour pressure of pure benzene is 745 torr

So, vapour pressure of benzene in solution = $0.340\times 745 torr$

= 253 torr

7 0

3 years ago

Why are space probes and other unmanned crafts more commonly used for space investigations than space crafts with crews of astro

Crank

All of these are correct.

4 0

2 years ago

g If 50.0 mL of a 0.75 M acetic acid solution is titrated with 1.0 M sodium hydroxide, what is the pH after 10.0 mL of NaOH have

V125BC [204]

Answer:

pH = 2.66

Explanation:

Acetic Acid + NaOH → Sodium Acetate + H₂O

First we <u>calculate the number of moles of each reactant</u>, using the <em>given volumes and concentrations</em>:

0.75 M Acetic acid * 50.0 mL = 37.5 mmol acetic acid

1.0 M NaOH * 10.0 mL = 10 mmol NaOH

We<u> calculate how many acetic acid moles remain after the reaction</u>:

37.5 mmol - 10 mmol = 27.5 mmol acetic acid

We now <u>calculate the molar concentration of acetic acid after the reaction</u>:

27.5 mmol / (50.0 mL + 10.0 mL) = 0.458 M

Then we <u>calculate [H⁺]</u>, using the<em> following formula for weak acid solutions</em>:

[H⁺] = $\sqrt{C*Ka}=\sqrt{0.458M*1.76x10^{-5}}$

[H⁺] = 0.0028

Finally we <u>calculate the pH</u>:

pH = -log[H⁺]

pH = 2.66

8 0

3 years ago