Question

Consider the following generic chemical equation. 2A+4B→3C What is the limiting reactant when each of the following amounts of A and B are allowed to react? Part A 2 molA; 5 molB 2 ; 5 B A SubmitRequest Answer Part B 1.8 molA; 4 molB 1.8 ; 4 B A SubmitRequest Answer Part C 3 molA; 4 molB 3 ; 4 B A SubmitRequest Answer Part D 22 molA; 40 molB 22 ; 40 B A

Answer 1

Answer:

A. Limiting reactant is A.

B. Limiting reactant is A.

C. Limiting reactant is B.

D. Limiting reactant is B.

Explanation:

It is possible to find the limiting reactant for a reaction taking the moles of a reactant that will react and using the chemical equation find the moles of the other reactant you will need.

For the reaction:

2A + 4B → 3C

A. 2 moles A requires:

2molA×$\frac{4molB}{2molA}$= 4moles of B

As you have 5 moles of B, limiting reactant is A.

B. 1,8 moles A requires:

1,8 molA×$\frac{4molB}{2molA}$= 3,6 moles of B

As you have 4 moles of B, limiting reactant is A.

C. 3 moles A requires:

3 molA×$\frac{4molB}{2molA}$= 6 moles of B

As you have just 4 moles of B, limiting reactant is B.

D. 22 moles A requires:

22 molA×$\frac{4molB}{2molA}$= 44moles of B

As you have just 40 moles of B, limiting reactant is B.

I hope it helps!