Answer:
I don't know were the statement are but here are the specs of each set
Step-by-step explanation:
Set A
mean; 83.83333
median; 87.5
mode; it has no mode
range; 147
Set B
mean; 67.08571
median; 3
mode; no mode
range; 376
hope this helps sorry for late answer :)
Answer: C
Step-by-step explanation:
You can write each term into a fraction.
![\sqrt[5]{x^4}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E4%7D)
becomes 
When you multiply 2 terms with the same base, you add the exponents.
is also the same as ![x\sqrt[5]{x^3}](https://tex.z-dn.net/?f=x%5Csqrt%5B5%5D%7Bx%5E3%7D)
You get this because ![\sqrt[5]{x^8} =\sqrt[5]{x*x*x*x*x*x*x*x}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E8%7D%20%3D%5Csqrt%5B5%5D%7Bx%2Ax%2Ax%2Ax%2Ax%2Ax%2Ax%2Ax%7D)
. When you pull out 5 os x, you are left with x³ on the inside.
Answer:
5
6
Step-by-step explanation:
To solve, collect like terms
x ≥ 2 + 21/2
x ≥ 4 1/2
the whole number that would be greater than 41/2 would be 5
2. 2.7 + 3.3 > x
6 > x
Answer: 1639.08
Step-by-step explanation: To find the surface area of a cylinder, multiply 2(3.14)times the radius squared. Your answer is 508.68. Then multiply 2(3.14)times the radius and the height. You'll get 1130.08. add the answers you got from both equations together. That's the surface area of your cylinder. If you have any more questions, please let me know.
Answer:
- the domain is [0,129]
- 112 mm
- 1942
Step-by-step explanation:
1. The function is good for years 1880 to 2009, 0 to 129 years after 1880. Values of x can be anything in the domain [0, 129].
__
2. 1950 -1880 = 70. The year 1950 corresponds to x=70, so the function tells us the water level rose ...
f(70) = 1.6·70 = 112 . . . . . mm
__
3. We want to find x when f(x) = 100. That will be the solution to ...
100 = 1.6x
100/1.6 = x = 62.5
Then 62.5 years after 1880 is year 1942.5. The water level was 100 mm higher than in 1880 in the year 1942.
