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2 years ago

If the Miller's spend $1200 on housing each month, then what is their total monthly budget?

Mathematics

1 answer:

wolverine [178]2 years ago

5 0

Answer:

2400$

Step-by-step explanation:

Miller's Family spends 50% of their budget on housing and we know that they spent 1200$ this month, so 1200$*2 = 2400$.

Have a nice day! :-)

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How do you get the answer for 10 millimeters increased by 30%

tiny-mole [99]

First you have to find what 30% of ten is, and then add it to the 10. So how do you find 30 % of 10? In math...

"of" means ×
"is" means =

30% of 10 is
30 % × 10 =

change 30% to a decimal by dividing by 100 ( move the decimal to the left 2 places)

.30 × 10 = 3

So 30% of ten is 3. Now since we are increasing by 30%, we have to add it to the original value, 10.

3 + 10 = 13

So 10 millimeters increased by 30% is

13 millimeters

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2 years ago

A scuba diver was rising back to the surface after taking photos under water. At 2:50 P.M.,

djverab [1.8K]

Answer:

the answer is 11.6 feet

Step-by-step explanation:

you simply subtract the feet of the depth he was at at 2:55pm from his depth at 2:50pm

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2 years ago

What is 362,000 rounded to the nearest ten thousand

Anon25 [30]

Answer:

360,000

Step-by-step explanation:

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2 years ago

Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 141 millimeters,

tiny-mole [99]

Answer:

Probability that the sample mean would be greater than 141.4 millimetres is 0.3594.

Step-by-step explanation:

We are given that Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 141 millimetres, and a standard deviation of 7.

A random sample of 39 steel bolts is selected.

Let $\bar X$ = sample mean diameter

The z score probability distribution for sample mean is given by;

Z = $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } } }$ ~ N(0,1)

where, $\mu$ = population mean diameter = 141 millimetres

$\sigma$ = standard deviation = 7 millimetres

n = sample of steel bolts = 39

Now, Percentage the sample mean would be greater than 141.4 millimetres is given by = P( $\bar X$ > 141.4 millimetres)

P( $\bar X$ > 141.4) = P( $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } } }$ > $\frac{141.4-141}{\frac{7}{\sqrt{39} } } }$ ) = P(Z > 0.36) = 1 - P(Z $\leq$ 0.36)

= 1 - 0.6406 = 0.3594

The above probability is calculated by looking at the value of x = 0.36 in the z table which has an area of 0.6406.

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3 years ago

How can we predict the sign of the product or quotient of sign numbers?

Andru [333]

Two positives make a positive
two negatives make a positive
1 negative and 1 positive make negative
1 positive and 1 negative make a negative

6 0

2 years ago