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Flauer [41]
3 years ago
15

stans cookie recipe makes 24 cookies and calls for exactly 384 sprinkles he is wondering how many sprinkles he would need to mak

e 60 cookies he assumes each cookie will have same number of sprinkles how many sprinkles does Stan need to make 60 cookies

Mathematics
2 answers:
Kisachek [45]3 years ago
7 0
He will need 960 sprinkles for 60 cookies.

This can be found by first finding how many sprinkles are on 1 cookie. To do this, you divide 384 by 24, to get 16 sprinkels on 1 cookie. Then you multiply 16 by 60 to get 960 (the number of sprinkles for 60 cookies).

I hope this helps!
Nina [5.8K]3 years ago
7 0

Answer:

Stan would need 960 sprinkles to make <u>60 cookies.</u>

Step-by-step explanation:

Hello, great question. These types are questions are the beginning steps for learning more advanced Algebraic Equations.

Since we are given 3 values, which are the <u>amount of sprinkles</u> to make<u> 24 cookies</u>, <u>60 cookies</u>, and give us one variable. We can use the Rule of Three technique to find the amount of sprinkles needed for <u>60 cookies</u>. This technique is shown in the picture that is attached below.

24 cookies   ⇒   384 sprinkles

60 cookies   ⇒   x

\frac{60*384}{24} = x

960 sprinkles = x

Therefore, we can see that Stan would need 960 sprinkles to make <u>60 cookies.</u>

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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UNO [17]

<u>Question 1</u>

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<u>Question 2</u>

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2 years ago
<img src="https://tex.z-dn.net/?f=12x%20%5E%7B2%7D%20%20%2B%204x%20%2B%2020" id="TexFormula1" title="12x ^{2} + 4x + 20" alt="1
Nesterboy [21]
<h3>Answer: </h3>

The GCF is 4

The polynomial factors to 4(3x^2+x+5)

==========================================================

Further explanation:

Ignore the x terms

We're looking for the GCF of 12, 4 and 20

Factor each to their prime factorization. It might help to do a factor tree, but this is optional.

  • 12 = 2*2*3
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Each factorization involves "2*2", which means 2*2 = 4 is the GCF here.

We can then factor like so

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The distributive property pulls out that common 4. We can verify this by distributing the 4 back in, so we get the original expression back again.

The polynomial inside the parenthesis cannot be factored further. Proof of this can be found by looking at the roots and noticing that they aren't rational numbers (use the quadratic formula).

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