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3 years ago

Determine the center and radius of the following circle equation: x ^ 2 + y ^ 2 - 6x + 2y - 39 = 0

1 answer:

4 0

X^2-6x+y^2+2y-39=0 =(x-3)^2 -9 + (y+1)^2 -1-39=0 so (x-3)^2 + (y+1)^2 = 49 . The center is at (3,-1) and the radius is 7 units.

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16 POINTS! NO LINKS! SHOW ALL WORK!

alexira [117]

Answer:

Step-by-step explanation:

f(3)= 3(3)-1

f(3)=9-1=8

f(x+1)= (x+1)^2-3(x+1)+2

=x^2+2x+1-3x-3+2

=x^2-x

8 0

2 years ago

Many games depend on how a ball bounces. For example, if different basketballs rebounded differently, one basketball would bounc

Crank

Answer:

Basketball = 0.743

Step-by-step explanation:

Given

Tennis:

Starting Height = 200 cm

Rebound Height = 111 cm

Soccer Balls;

Starting Height = 200 cm

Rebound Height = 120 cm

Basketball:

Starting Height = 72 inches

Rebound Height = 53.5 inches

Squash:

Starting Height = 100 inches

Rebound Height = 29.5 inches

For measuring the bounciness of a ball, one needs that starting Height of and the rebound Height of that ball which have been listed out above.

Calculating the rebound ratio of each balls.

Rebound Ratio = Rebound Height/Starting Height

Tennis: 111/200= 0.556

Soccer Balls: 120/200 = 1.667

Basketball: 53.5/72 = 0.743

Squash: 29.5/100 = 0.295

From the rebounding ratio calculated above, it can be seen that basketball has the highest rebound ratio of 0.743 and is the bounciest of all whole Squash has the least rebound of 0.295 ratio, hence it is the least bounce of all.

8 0

3 years ago

Brainlyest for best answer

bazaltina [42]

Answer:

Step-by-step explanation:

Add all of the numbers together then divide by 5

7 0

2 years ago

Read 2 more answers

A sociologist was investigating the ages of grandparents of high school students. From a random sample of 10 high school student

umka2103 [35]

Answer:

$(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908$

$(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308$

So then the confidence interval for the difference of means is given by:

$-8.908 \leq \mu_M -\mu_F \leq 5.308$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_{M}= 69.8$ represent the mean for the age of grandmother

$\bar X_{F}= 71.6$ represent the mean for the age of grandfather

$s_{M}= 8.38$ represent the sample deviation for the age of grandmother

$s_{F}= 6.65$ represent the sample deviation for the age of grandfather

$n_M = n_F= 10$

Solution to the problem

For this case the confidence interval is given by:

$(\bar X_{M} -\bar X_F) \pm t_{\alpha/2} \sqrt{\frac{s^2_M}{n_M} +\frac{s^2_F}{n_F}}$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n_M +n_F-2=10+10-2=18$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,18)".And we see that $t_{\alpha/2}=2.101$