Using statistical concepts, it is found that:
- 2 modes would be expected for the distribution.
- The distribution would be symmetric.
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- Heights are traditionally normally distributed, which is a symmetric distribution.
- Second-grade students are considerably shorter than college students, so there would be two modes.
- Both distributions, for the height of second grade and of college students, are normal, which is symmetric, thus the combined distribution will also be symmetric.
A similar problem is given at brainly.com/question/13460485
Answer:
5,380,000
Step-by-step explanation:
Answer:
three x a mumber is 18 that is the answer
<span>You can calculate the following probabilities:
1. Given that a sampled student is in the Spanish Club, what is the probability they got the Spanish class they requested?
2. Given that a sampled student is not in the Spanish Club, what is the probability they got the Spanish class they requested? If there is a significant difference between the two probabilities, it indicates there is a bias in the selection procedure.
</span><span>Given that, a sampled student is in the Spanish Club, the probability they got the Spanish class they requested is given by 265/335. Given that, a sampled student is not in the Spanish Club, the probability they got the Spanish class they requested is given by 100/165.
</span>
<span>If a student is at the Spanish club, the probability they got the Spanish class they requested is 265/335 = 0.79. If a student is not in the Spanish club, the probability they got the Spanish class they requested is 100/165 = 0.61.
</span>
<span>Based on the calculation, all students do not have an equal chance of getting into the Spanish class that they requested.</span>
Answer:
y = 5x -3
Step-by-step explanation:
y = mx + b
b is the y intercept, so you can replace b with -3
m is the slope so you can replace m with 5
and you get your answer y = 5x - 3
