Among the following scientists, which one is known for developing the laws of heredity?

Buyer's remorse, a mild form of _______, is the internal conflict that arises from an inconsistency (disharmony) between competi

Paha777 [63]

Buyer's remorse, a mild form of cognitive dissonance, is the internal conflict that arises from an inconsistency (disharmony) between competing beliefs, or between beliefs and behavior.

Explanation:

In the psychology field, the occurrence when a person retains two or more contradictory views, ideas, or values, or takes part in a behavior that runs counter to one of these three, and thereby encounters psychological stress is understood as "cognitive dissonance".

For instance, when humans smoke (behavior) and realize that smoking causes cancer (cognition), thus they are considered in a cognitive dissonance situation. It is used as a concentration on more positive beliefs which outweigh dissonant ideology or behaviour.

5 0

3 years ago

The type of fibrous joints that are immobile and found only between certain bones of the skull are called

Lesechka [4]

Somebody once told me the world is gonna roll me
I ain't the sharpest tool in the shed
She was looking kind of dumb with her finger and her thumb
In the shape of an "L" on her forehead

Well the years start coming and they don't stop coming
Fed to the rules and I hit the ground running
Didn't make sense not to live for fun
Your brain gets smart but your head gets dumb
So much to do, so much to see
So what's wrong with taking the back streets?
You'll never know if you don't go
You'll never shine if you don't glow

Hey now, you're an all-star, get your game on, go play
Hey now, you're a rock star, get the show on, get paid
And all that glitters is gold
Only shooting stars break the mold

It's a cool place and they say it gets colder
You're bundled up now, wait till you get older
But the meteor men beg to differ
Judging by the hole in the satellite picture
The ice we skate is getting pretty thin
The water's getting warm so you might as well swim
My world's on fire, how about yours?
That's the way I like it and I never get bored

Hey now, you're an all-star, get your game on, go play
Hey now, you're a rock star, get the show on, get paid
All that glitters is gold
Only shooting stars break the mold

Hey now, you're an all-star, get your game on, go play
Hey now, you're a rock star, get the show, on get paid
And all that glitters is gold
Only shooting stars

Somebody once asked could I spare some change for gas?
I need to get myself away from this place
I said yep what a concept
I could use a little fuel myself
And we could all use a little change

Well, the years start coming and they don't stop coming
Fed to the rules and I hit the ground running
Didn't make sense not to live for fun
Your brain gets smart but your head gets dumb
So much to do, so much to see
So what's wrong with taking the back streets?
You'll never know if you don't go (go!)
You'll never shine if you don't glow

Hey now, you're an all-star, get your game on, go play
Hey now, you're a rock star, get the show on, get paid
And all that glitters is gold
Only shooting stars break the mold

And all that glitters is gold
Only shooting stars break the mold

8 0

3 years ago

In Drosophila melanogaster, vestigial wings (vg) is recessive to normal wings (vg+), black body (b) is recessive to gray body (b

yan [13]

Correct progeny phenotype:

1779 vestigial wings, black body and purple eyes, vg b pr
1665 normal wings, a grey body and red eyes, vg+ b+ pr+
252 normal wings, an black body and purple eyes, vg+ b pr
241 vestigial wings, a gray body and red eyes, vg b+ pr+
131 normal wings, an black body and red eyes, vg +b pr+
118 vestigial wings, a gray body and purple eyes, vg b+ pr
13 vestigial wings, an black body and red eyes, vg b pr+
9 normal wings, a gray body and purple eyes, vg+ b+ pr

Answer:

The order of these genes is vg --- pr --- b
Map distances between the genes vg/pr = 12.2 MU
Map distance between the genes pr/b = 6.4 MU
Map distances between the genes vg/b = 18.6 MU

Explanation:

We know that

•Normal wings expressed by vg+ is dominant over vestigial wings, vg

•Gray body b+ is dominant over black body

•Red eyes, pr+, is dominant over purple ayes, pr

We have the number of descendants of each phenotype product of the tri-hybrid cross.

•1779 vestigial wings, black body and purple eyes vg b pr

•1665 normal wings, a grey body and red eyes vg+ b+ pr+

•252 normal wings, an black body and purple eyes vg+ b pr

•241 vestigial wings, a gray body and red eyes vg b+ pr+

•131 normal wings, an black body and red eyes vg +b pr+

• 118 vestigial wings, a gray body and purple eyes vg b+ pr

•13 vestigial wings, an black body and red eyes vg b pr+

• 9 normal wings, a gray body and purple eyes vg+ b+ pr

The total number of individuals is 4208.

In a tri-hybrid cross, it can occur that the three genes assort independently or that two of them are linked and the third not, or that the three genes are linked. In this example, in particular, the three genes are linked on the same chromosome.

Knowing that the genes are linked, we can calculate genetic distances between them. First, we need to know their order in the chromosome, and to do so, we need to compare the genotypes of the parental gametes with the ones of the double recombinants. We can recognize the parental gametes in the descendants because their phenotypes are the most frequent, while the double recombinants are the less frequent. So:

Parental)

1779 vestigial wings, black body and purple eyes vg b pr

1665 normal wings, a grey body and red eyes vg+ b+ pr+

Double recombinant)

13 vestigial wings, an black body and red eyes vg b pr+
9 normal wings, a gray body and purple eyes vg+ b+ pr

Simple recombinant)

252 normal wings, an black body and purple eyes vg+ b pr
241 vestigial wings, a gray body and red eyes vg b+ pr+
131 normal wings, an black body and red eyes vg +b pr+
118 vestigial wings, a gray body and purple eyes vg b+ pr

Comparing parental with the double recombinants we will realize that between

vg b pr (parental)

vg b pr+ (double recombinant)

and

vg+ b+ pr+ (Parental)

vg+ b+ pr (double recombinant)

They only change in the position of the alleles pr/pr+. This suggests that the position of the gene pr is in the middle of the other two genes, vg and b, because in a double recombinant only the central gene changes position in the chromatid.

So, the order of the genes is:

---- vg ---- pr -----b ----

Now we will call Region I to the area between vg and pr and Region II to the area between pr and b.

Once established the order of the genes we can calculate distances between them, and we will do it from the central gene to the genes on each side. First We will calculate the recombination frequencies, and we will do it by region. We will call P1 to the recombination frequency between vg and pr genes, and P2 to the recombination frequency between pr and b.

P1 = (R + DR) / N

P2 = (R + DR)/ N

Where: R is the number of simple recombinants in each region, DR is the number of double recombinants in each region, and N is the total number of individuals.

So:

Parental)

• 1779 vestigial wings, black body and purple eyes vg pr b

• 1665 normal wings, a grey body and red eyes vg+ pr+ b+

Double recombinant)

• 13 vg pr+ b

• 9 vg+ pr b+

Simple recombinant)

• 252 vg+ pr b

• 241 vg pr+ b+

• 131 vg+ pr+ b

• 118 vg pr b+

P1 = (R + DR) / N

P1 = (252+241+13+9)/4208

P1 = 515/4208

P1 = 0.122

P2= (R + DR) / N

P2 = (131+118+13+9)/4208

P2 = 271/4208

P2 = 0.064

Now, to calculate the recombination frequency between the two extreme genes, vg and b, we can just perform addition or a sum:

P1 + P2= Pt

0.122 + 0.064 = Pt

0.186=Pt

The genetic distance will result from multiplying that frequency by 100 and expressing it in map units (MU). One centiMorgan (cM) equals one map unit (MU).

The map unit is the distance between the pair of genes. Every 100 meiotic products, one of them results in a recombinant product. Now we must multiply each recombination frequency by 100 to get the genetic distance in map units:

GD1= P1 x 100 = 0.122 x 100 = 12.2 MU

GD2= P2 x 100 = 0.064 x 100 = 6.4 MU

GD3=Pt x 100 = 0.186 x 100 = 18.6 MU

---- vg ---------------------- pr ---------------------b ----

R1 R2

-----vg----12.2MU---------pr—

----pr--------6.4 MU----b—

-----vg ----------------18.6 MU--------------------b----

3 0

3 years ago

Why is training at your target heart rate important?

viva [34]

It is important because you need to increase your heart rate by being more active because it will help you build your strength

6 0

4 years ago

When a patient comes to a hospital with severe dehydration, doctors will give

sleet_krkn [62]

Answer:

The red blood cells could burst.

Explanation:

If they are given pure water, the IV fluid will be hypotonic to the blood cells. That means water will end the red blood cells by osmosis, from a high concentration outside to a lower concentration inside.

This will result in the red blood cells becoming swollen and even potential bursting.

7 0

3 years ago