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3 years ago

(please help) look at the picture below

Mathematics

1 answer:

aev [14]3 years ago

8 0

Answer: 0.75 . Work is shown below

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Worker A earns $7.90 per widget produced, produces 14 widgets per day, and works 10 hours per day. Worker B earns $9.00 per widg

Otrada [13]

The answer is D worker A earns more per day but less per hour

7 0

3 years ago

Read 2 more answers

Mr.rodriguez bought 420 pencils for the school.if there are 10 pencils In each box how many boxes are there'

Sophie [7]

$420 \div 10 = 42$

3 0

4 years ago

Read 2 more answers

In a simple random sample of 300 boards from this shipment, 12 fall outside these specifications. Calculate the lower confidence

Lyrx [107]

Answer:

The 95% confidence interval for the percentage of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

Step-by-step explanation:

In a random sample of 300 boards the number of boards that fall outside the specification is 12.

Compute the sample proportion of boards that fall outside the specification in this sample as follows:

$\hat p =\frac{12}{300}=0.04$

The (1 - α)% confidence interval for population proportion p is:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

The critical value of z for 95% confidence level is,

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Use a z-table.

Compute the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification as follows:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.04\pm1.96\sqrt{\frac{0.04(1-0.04)}{300}}\\=0.04\pm0.022\\=(0.018, 0.062)\\\approx(1.8\%, 6.2\%)$

Thus, the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

6 0

3 years ago

Which of the following sets of values correctly completes the t-chart for the equation y = 2x2 - 1.

natali 33 [55]

Answer:

The sets of values that correctly completes the t-chart are:

7, -1, 7

Hence, option B is true.

Step-by-step explanation:

Given the equation

y = 2x² - 1

FOR x = -2

substitute x = -2 in the equation

y = 2x² - 1

y = 2(-2)² - 1

y = 8 - 1

y = 7

FOR x = 0

substitute x = 0 in the equation

y = 2x² - 1

y = 2(0)² - 1

y = -1

FOR x = 2

substitute x = 2 in the equation

y = 2x² - 1

y = 2(2)² - 1

y = 8 - 1

y = 7

Thus, the t-chart becomes:

x y

-2 7

0 -1

2 7

Thus, the sets of values that correctly completes the t-chart are:

7, -1, 7

Hence, option B is true.

7 0

3 years ago

Evaluate each expression if x = −2, y = −3, and z = 5.

Scrat [10]

Basically what you have to do is substitute the variables for the values

-4+-9+5= -8
-2-3= -5
2= 2
6-4+1= 3
-9(-2+-4--3)= 27

3 0

4 years ago