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strojnjashka [21]
3 years ago
14

The adult skeleton consists of 206 bones. There are 28 bones in the skull and 30 bones in the arms and legs. Out of the 28 skull

bones, 14 are facial bones, 6 are ear bones and 8 are cranial bones. How many more bones are there in the arms and legs than in the face?
Mathematics
2 answers:
telo118 [61]3 years ago
5 0

Answer:

There are <u>16</u> more bones in the arms and legs than in the face.

Step-by-step explanation:

Please mark brainliest

Kruka [31]3 years ago
5 0
<h3>Hello there i hope you are having a good day :) your question: The adult skeleton consists of 206 bones. There are 28 bones in the skull and 30 bones in the arms and legs. Out of the 28 skull bones, 14 are facial bones, 6 are ear bones and 8 are cranial bones. How many more bones are there in the arms and legs than in the face?</h3><h3>So firstly a Adults have 206 bones in their bones and a baby is born with 300 more bones but are fused together when the baby grows up. So 206 bones are in the arms and legs which is 120 then there is 28 bone the skull so the answer should be 120 bones all together.</h3><h3>Hopefully this helps you ❤</h3>
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Find surface area of rectangular prism
DIA [1.3K]

Answer:

806 yd sq.

Step-by-step explanation:

Area=(length)(width), so to find the surface area you can just find the area of each side and then add then all together.

They already gave you the length of some of the sides, so you should use that to help you find the length of all the sides.

You can see the entire prism's length is 17 yd, width is 4 yd, and height is 14 yd.

The large visible side's area would be (14)(17)= 283 yd. There's another one of these side's on the other side that we can't see. So we would do (283)(2) = 566 yd sq.

Next, we'll find the area of the side on the side by doing (14)(4)=56. Once again, there's two of these sides so we do (56)(2) to get 112 yd sq for this side.

Finally, we'll find the area of the top side. We can do (4)(17) =68, and then (68)(2) to get 138 yd sq.

Now, we have the area of each side of the prism! To find the total surface area, just add them all together. 556+112+138=806.

The surface area would be 806 yd sq.

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2 years ago
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The value of gold in the year 2010 was approximately $1,800. The value of gold increases by approximately 9.5% a year.
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Answer: 1800e^(.95*x)
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2 years ago
The line 5x – 5y = 2 intersects the curve x2y – 5x + y + 2 = 0 at
inna [77]

Answer:

(a) The coordinates of the points of intersection are (-2, -12/5), (2/5, 0), and (2, 8/5)

(b) The gradient of the curve at each point of intersection are;

Gradient at (-2, -12/5) = -0.92

Gradient at (2/5, 0) = 4.3

Gradient at (2, 8/5) = -0.28

Step-by-step explanation:

The equations of the lines are;

5·x - 5·y = 2......(1)

x²·y - 5·x + y + 2 = 0.......(2)

Making y the subject of equation (1) gives;

5·y = 5·x - 2

y = (5·x - 2)/5

Making y the subject of equation (2) gives;

y·(x² + 1) - 5·x + 2 = 0

y = (5·x - 2)/(x² + 1)

Therefore, at the point the two lines intersect their coordinates are equal thus we have;

y = (5·x - 2)/5 = y = (5·x - 2)/(x² + 1)

Which gives;

\dfrac{5 \cdot x - 2}{5} = \dfrac{5 \cdot x - 2}{x^2 + 1}

Therefore, 5 = x² + 1

x² = 5 - 1 = 4

x = √4 = 2

Which is an indication that the x-coordinate is equal to 2

The y-coordinate is therefore;

y = (5·x - 2)/5 = (5 × 2 - 2)/5 = 8/5

The coordinates of the points of intersection = (2, 8/5}

Cross multiplying the following equation

Substituting the value for y in equation (2) with (5·x - 2)/5 gives;

\dfrac{5 \cdot x^3 - 2 \cdot x^2 - 20 \cdot x + 8}{5} = 0

Therefore;

5·x³ - 2·x² - 20·x + 8 = 0

(x - 2)×(5·x² - b·x + c) = 5·x³ - 2·x² - 20·x + 8

Therefore, we have;

x²·b - 2·x·b -x·c + 2·c -5·x³ + 10·x²

5·x³ - 10·x² - x²·b + 2·x·b + x·c - 2·c = 5·x³ - 2·x² - 20·x + 8

∴ c = 8/(-2) = -4

2·b + c = - 20

b = -16/2 = -8

Therefore;

(x - 2)×(5·x² - b·x + c) = (x - 2)×(5·x² + 8·x - 4)

(x - 2)×(5·x² + 8·x - 4) = 0

5·x² + 8·x - 4 = 0

x² + 8/5·x - 4/5  = 0

(x + 4/5)² - (4/5)² - 4/5 = 0

(x + 4/5)² = 36/25

x + 4/5 = ±6/5

x = 6/5 - 4/5 = 2/5 or -6/5 - 4/5 = -2

Hence the three x-coordinates are

x = 2, x = - 2, and x = 2/5

The y-coordinates are derived from y = (5·x - 2)/5 as y = 8/5, y = -12/5, and y = y = 0

The coordinates of the points of intersection are (-2, -12/5), (2/5, 0), and (2, 8/5)

(b) The gradient of the curve, \dfrac{\mathrm{d} y}{\mathrm{d} x}, is given by the differentiation of the equation of the curve, x²·y - 5·x + y + 2 = 0 which is the same as y = (5·x - 2)/(x² + 1)

Therefore, we have;

\dfrac{\mathrm{d} y}{\mathrm{d} x}= \dfrac{\mathrm{d} \left (\dfrac{5 \cdot x - 2}{x^2 + 1}  \right )}{\mathrm{d} x} = \dfrac{5\cdot \left ( x^{2} +1\right )-\left ( 5\cdot x-2 \right )\cdot 2\cdot x}{\left (x^2 + 1 ^{2} \right )}.......(3)

Which gives by plugging in the value of x in the slope equation;

At x = -2, \dfrac{\mathrm{d} y}{\mathrm{d} x} = -0.92

At x = 2/5, \dfrac{\mathrm{d} y}{\mathrm{d} x} = 4.3

At x = 2, \dfrac{\mathrm{d} y}{\mathrm{d} x} = -0.28

Therefore;

Gradient at (-2, -12/5) = -0.92

Gradient at (2/5, 0) = 4.3

Gradient at (2, 8/5) = -0.28.

7 0
3 years ago
Which expression does sine of the quantity pi plus theta end quantity plus cosine of the quantity pi over 2 minus theta end quan
LiRa [457]

Answer:

  (c)  0

Step-by-step explanation:

Each of the terms in the expression represents a different transformation of a different trig function. Expressing those as the same trig function can make it easier to find the sum.

__

We can start with the identity ...

  cos(x) = sin(x +π/2)

Substituting the argument of the cosine function in the given expression, we have ...

  cos(π/2 -θ) = sin((π/2 -θ) +π/2) = sin(π -θ) = -sin(θ -π)

__

The first term, sin(π +θ), is a left-shift of the sine function by 1/2 cycle, so can be written ...

  sin(π +θ) = -sin(θ)

The second term is the opposite of a right-shift of the sine function by 1/2 cycle, so can be written ...

  cos(π/2 -θ) = -sin(θ -π) = sin(θ)

Then the sum of terms is ...

  sin(π +θ) +cos(π/2 -θ) = -sin(θ) +sin(θ) = 0

The sum of the two terms is identically zero.

5 0
2 years ago
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