The work done (in foot-pounds) in stretching the spring from its natural length to 0.7 feet beyond its natural length is 1.23 foot-pound
<h3>Data obtained from the question</h3>
From the question given above, the following data were obtained:
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Work done (Wd) =?
<h3>How to determine the spring constant</h3>
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Spring constant (K) =?
F = Ke
Divide both sides by e
K = F/ e
K = 3 / 0.6
K = 5 pound/foot
Thus, the spring constant of the spring is 5 pound/foot
<h3>How to determine the work done</h3>
- Spring constant (K) = 5 pound/foot
- Extention (e) = 0.7 feet
- Work done (Wd) =?
Wd = ½Ke²
Wd = ½ × 5 × 0.7²
Wd = 2.5 × 0.49
Wd = 1.23 foot-pound
Therefore, the work done in stretching the spring 0.7 feet is 1.23 foot-pound
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Y - 3 = 1/2 (x + 4)
y - 3 = 1/2 x + 2
1/2x + 2 = y - 3
1/2x - y = -3 - 2
1/2x - y = -5 answer
Answer:
Since the part we can see is half of the whole figure, and there are six sides then in total there are 12 sides. A "12-gon" is called a dodecahedron. This is the answer.
Answer:
180 cm^3
Step-by-step explanation:
A=lw
A=20×9
A=180
42 (1- 25/100) = 63/2 = 31.5 dollars
answer is $31.50
hope it helps
