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svet-max [94.6K]
2 years ago
7

I know this question is easy, but I don’t really know how to do it? Help? If possible put a quick explanation, it’s fine if not!

!

Mathematics
1 answer:
lorasvet [3.4K]2 years ago
3 0

Answer:

She left $10.62 the total was $58.87

Hope this helps :)

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A³b² a²b simplify the following expression
liberstina [14]

Answer:

a^{5}b^{3}

Step-by-step explanation:

The law of indices can be used to simplify mathematical expressions involving  arithmetical operation on variables with powers.

a^{m} x a^{n} = a^{(m+n)}

Thus, the given expression can be simplified as follows:

a³b² a²b  = a³ x a² x b² x b^{1}

               = a^{3+2} x b^{2+1}

               = a^{5}b^{3}

Thus,

a³b² a²b  = a^{5}b^{3}

7 0
2 years ago
A box of Georgia peaches has 3 bad and 12 good peaches. (a) If you make a peach cobbler of 12 peaches randomly selected from the
Eddi Din [679]

Answer:

a) 0.21% probability that there are no bad peaches in the peach cobbler.

b) 99.79% probability of having at least 1 bad peach in the peach cobbler

c) 7.91% probability of having exactly 2 bad peaches in the peach cobbler.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the peaches are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

(a) If you make a peach cobbler of 12 peaches randomly selected from the box, what is the probability that there are no bad peaches in the peach cobbler?

Desired outcomes:

12 good peaches, from a set of 12. So

D = C_{12,12} = \frac{12!}{12!(12 - 12)!} = 1

Total outcomes:

12 peaches, from a set of 15. So

T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455

Probability:

p = \frac{D}{T} = \frac{1}{455} = 0.0021

0.21% probability that there are no bad peaches in the peach cobbler.

(b) What is the probability of having at least 1 bad peach in the peach cobbler?

Either there are no bad peaches, or these is at least 1. The sum of the probabilities of these events is 100%. So

p + 0.21 = 100

p = 99.79

99.79% probability of having at least 1 bad peach in the peach cobbler

(c) What is the probability of having exactly 2 bad peaches in the peach cob- bler?

Desired outcomes:

2 bad peaches, from a set of 3.

One good peach, from a set of 12.

D = C_{3,2}*C_{12,1} = \frac{3!}{2!(3-2)!}*\frac{12!}{1!(12 - 1)!} = 36

Total outcomes:

12 peaches, from a set of 15. So

T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455

Probability:

p = \frac{D}{T} = \frac{36}{455} = 0.0791

7.91% probability of having exactly 2 bad peaches in the peach cobbler.

3 0
3 years ago
I need the answer asap .! help please !
shtirl [24]

Answer:

i tried the math and if im correct it should be 0.52N

Step-by-step explanation:

im sorry if its not correct bro

8 0
2 years ago
What the volume is of this solid
mrs_skeptik [129]

Answer:

336.

Step-by-step explanation:

8 x 7 x 6 = 336.

Feel free to let me know if you need more help! :)

5 0
2 years ago
Answer the MATH question pleaaseee
Mrac [35]

Answer:

25 percent

Step-by-step explanation:

3 0
2 years ago
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