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2 years ago

Which is the solution set of the inequality 15y-9 < 36?

Mathematics

2 answers:

Kipish [7]2 years ago

6 0

15y<36-9 ==>15y<27

y<27/15 ==>y<9/5

answer is B

lozanna [386]2 years ago

5 0

Answer:

The correct answer option is C. y < 3.

Step-by-step explanation:

We are given the following inequality and we are to solve it in terms of y and find its solution set:

$15y - 9 < 36$

Taking the constants to one side of the inequality and variable at the other side to get:

$15y < 36 + 9$

$15y < 45$

$y < \frac {45} {15}$

$y < 3$

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X + 8 + 2x <= 2x + 13

sergejj [24]

Answer:

X = 15

Step-by-step explanation:

We move all terms to the left:

x+8+2x-(2x+13)=0

We add all the numbers together, and all the variables:

3x-(2x+13)+8=0

We get rid of parentheses:

3x-2x-13+8=0

We add all the numbers together, and all the variables:

x-5=0

We move all terms containing x to the left, all other terms to the right:

x=5

5 0

2 years ago

Solve on the interval 0,2pi) 2cscx-3=-5

nydimaria [60]

We have that

2cscx-3=-5---------> 2cscx=-5+3---------> cscx=-2/2---------> cscx=-1

we know that
csc x=1/sin x
then
1/sin x=-1--------------> sin x=-1
x=arcsin (-1)---------> x=-90°
x=-90°---------------> 360°-90°-----------> x=270°------------> 3pi/2

the answer is
x=3pi/2 radians

4 0

3 years ago

An image of two concentric circles is shown with r2 = 6 and r1 = 2:

AysviL [449]

The radius of the Outer circle (with r₂) is 6 and the radius of the inner circle (with r₁) is 2. When objects are similar, they have a proportional relationship. If we take the outer circle and squeeze by one third, we get a radius of 6 x 1/3 = 2. On the other hand, if we start with the inner circle and stretch it by 3, we get a radius of 2 x 3 = 6.

Thus, to make r₂ similar, we use a scale factor of 1/3. The third choice is best.

5 0

2 years ago

Lucas used the number sentence 8 x 2 = 16 to solve a problem. Which problem could he have solved?

4vir4ik [10]

Answer:

Word problem 3

Step-by-step explanation:

Word Problem one is a subtraction problem since Felicia is giving away two marbles to Lucas. Word Problem two is a division problem since Felicia is evenly dividing the number of marbles she has into two bags. Word Problem three is a multiplication problem because Ryan has two times as many marbles that Felicia does. Word Problem four is an addition problem because she found two more marbles while she already has eight marbles. Keywords for subtraction word problems are: fewer than, decrease, take away, less than, minus, difference, change, lost reduced, and subtract. Keywords for division word problems are: As much, cut up, groups, equally, sharing, half, how many in each, parts, per percent, quotient, ratio, and separated. Keywords for multiplication word problems are: double, every, factor, increased, multiplied product, times, and tripled.

3 0

2 years ago

4 employees drive to work in the same car. the workers claim they were late to work because of a flat tire. their managers ask t

Brums [2.3K]

Answer:

The required probability is 0.015625.

Step-by-step explanation:

Consider the provided information.

There number of tires are 4.

The number of workers are 4.

The probability that individual select front drivers side tire = $\frac{1}{4}$

The probability that they all select front drivers side,tire is: $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}=\frac{1}{256}$

Similarly,

The probability that they all select front passenger side, tire is: $\frac{1}{256}$

The probability that they all select rear driver side,tire is: $\frac{1}{256}$

The probability that they all select rear passenger side, tire is: $\frac{1}{256}$

Hence, the probability that all four workers select the same tire = $\frac{1}{256}+ \frac{1}{256}+\frac{1}{256}+\frac{1}{256}$

the probability that all four workers select the same tire = $\frac{4}{256}=\frac{1}{64}=0.015625$

Hence, the required probability is 0.015625.

5 0

3 years ago