Parameterize the lateral face

of the cylinder by

where

and

, and parameterize the disks

as


where

and

.
The integral along the surface of the cylinder (with outward/positive orientation) is then




Answer: 30.21$
Explanation:
1. 38• 0.25(25%)=28.50
2. 28.50•0.06(6)=1.71 ( the sales taxes)
3. 28.50+1.71=30.21$
Hope this helps. If it’s correct please tell me.
The graphed polynomial seems to have a degree of 2, so the degree can be 4 and not 5.
<h3>
Could the graphed function have a degree 4?</h3>
For a polynomial of degree N, we have (N - 1) changes of curvature.
This means that a quadratic function (degree 2) has only one change (like in the graph).
Then for a cubic function (degree 3) there are two, and so on.
So. a polynomial of degree 4 should have 3 changes. Naturally, if the coefficients of the powers 4 and 3 are really small, the function will behave like a quadratic for smaller values of x, but for larger values of x the terms of higher power will affect more, while here we only see that as x grows, the arms of the graph only go upwards (we don't know what happens after).
Then we can write:
y = a*x^4 + c*x^2 + d
That is a polynomial of degree 4, but if we choose x^2 = u
y = a*u^2 + c*u + d
So it is equivalent to a quadratic polynomial.
Then the graph can represent a function of degree 4 (but not 5, as we can't perform the same trick with an odd power).
If you want to learn more about polynomials:
brainly.com/question/4142886
#SPJ1
What are the choices so that we Can help you appropriately
OQ is equal to QP so the first option is correct