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balandron [24]
3 years ago
10

I was doing great but then I got confused with 3. 1. 2.

Mathematics
1 answer:
Mazyrski [523]3 years ago
8 0
For number 1 I think it is 1.02n because I added the like terms together
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Y=x-5; domain = {4,6,8}
Lostsunrise [7]

Answer:

Range = {-1, 1, 3}

Step-by-step explanation:

<u><em>The question asks for the range.</em></u>

The function given is

y=x-5

The domain is the set of 3 numbers:

Domain = {4,6,8}

We need to find the range.

First, the range is the set of all y-values for which the function is defined.

When we will be given the domain with a set of numbers, the range would be the numbers that we get when we evaluate the the function at those numbers.

So, we evaluate the function (y-values) at x = 4,6, and 8.

At x = 4:

y=x-5\\y=4-5\\y=-1

At x = 6:

y=x-5\\y=6-5\\y=1

At x = 8:

y=x-5\\y=8-5\\y=3

Thus, the range is:

Range = {-1, 1, 3}

7 0
3 years ago
the ages of amit and archana are in ratio of 4:5 if amit age is 4 years 8 month old.find the age of archana
xxTIMURxx [149]
For easier calculation,
convert 4years 8months into months. This would give you 56months.
Amit is 56months old.
4 units/proportion =56
1 unit=56/4
5unit=56/4 ×5(simplify)
7 0
3 years ago
BRAINLIEST FOR CORRECT ANSWER
user100 [1]
2 times 2.5 times 1.5 times 10 equals to 75 square meters.
4 0
3 years ago
Which relation is a function?
bixtya [17]
Answer is the first one on left
4 0
2 years ago
Read 2 more answers
Need help for question 8 and 9. I need the equation that’s passes through the points!
dsp73

Answer:

Step-by-step explanation:

Question 8

Let the equation of a line passing through two points (x_1,y_1) and (x_2,y_2) is given by,

y = mx + b

Here, m = slope and y-intercept = b

Since, m = \frac{y_2-y_1}{x_2-x_1}

For two points (1, 4) and (5, 8),

m = \frac{8-4}{5-1}

m = 1

Equation will be,

y = (1)x + b

y = x + b

Since, this line passes through (1, 4),

4 = 1 + b

b = 3

Therefore, equation of the line will be,

y = x + 3

Question 9

Let the equation is y = mx + b

m = \frac{y_2-y_1}{x_2-x_1}

For two points (2, 10) and (6, 4)

m = \frac{10-4}{2-6}

m = -\frac{3}{2}

By substituting the value of 'm' in the equation,

y = -\frac{3}{2}x+b

Since, this line passes through (2, 10)

10 = -\frac{3}{2}(2)+b

b = 10 + 2

b = 12

Therefore, equation of the line will be,

y=-\frac{3}{2}x+12

4 0
3 years ago
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