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UNO [17]
3 years ago
5

Can someone please help ???

Mathematics
1 answer:
ivanzaharov [21]3 years ago
6 0

\begin{array}{l}\text{Let\ x\ be\ the\ third\ side,\ then,\ by\ Pitagoras}\\\\x^{2} +5^{2} =\left(\sqrt{61}\right)^{2}\\\\\Longrightarrow x^{2} =61-25\\\\\Longrightarrow x=\sqrt{36} =6\end{array}

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artcher [175]

Answer:

1 7/12

Step-by-step explanation:

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Step-by-step explanation:

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<u>Given</u>:

Given that FGH is a right triangle. The sine of angle F is 0.53.

We need to determine the cosine of angle H.

<u>Cosine of angle H:</u>

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This can be written as,

sin F=0.53

Applying the trigonometric ratio, we have;

\frac{HG}{FH}=0.53 ----- (1)

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Substituting the value from equation (1) in equation (2), we get;

cos \ H=0.53

Thus, the cosine of angle H is 0.53

6 0
3 years ago
Please help. It’s due today
vladimir1956 [14]

Answer:

There's nothing there I believe you forgot to add a link just add or create another question and i'll see what I can do :)

Step-by-step explanation:

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