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3 years ago

What is the correct answer?

Chemistry

1 answer:

densk [106]3 years ago

8 0

Answer:

I think the answer is (a)-repeat the experiment using a larger sample size

I hope I can answer your question!

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3 years ago

Why would there be a concern with glaciers melting because of global warming?

vaieri [72.5K]

The correct answer is C. because it could lead to an increase in ocean levels

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3 years ago

The magnitude of an earthquake, measured on the Richter Scale, is M log1o T where / is the amplitude registered on a seismograph

just olya [345]

<u>Answer:</u> The magnitude rating for an earthquake causing an amplitude 10,000,000 times $I_o$ is 7.

<u>Explanation:</u>

Richter scale is defined as the scale which expresses the magnitude of earthquake on the basis of the seismograph oscillations.

The equation used to measure the magnitude of an earthquake on Richter scale is:

$M=log_{10}\frac{I}{I_o}$

where

I = amplitude registered on seismograph 100 km away from seismic center = $10,000,000I_o$

$I_o$ = small amplitude

Putting values in above equation, we get:

$M=\log_{10}(\frac{10000000I_o}{I_o})\\\\M=7$

Hence, the magnitude rating for an earthquake causing an amplitude 10,000,000 times $I_o$ is 7.

8 0

3 years ago

The half-life of nitrogen-13 is 10.0 minutes. if you begin with 53.3 mg of this isotope, what mass remains after 25.9 minutes ha

zimovet [89]

Hello!

The half-life is the time of half-disintegration, it is the time in which half of the atoms of an isotope disintegrate.

We have the following data:

mo (initial mass) = 53.3 mg

m (final mass after time T) = ? (in mg)

x (number of periods elapsed) = ?

P (Half-life) = 10.0 minutes

T (Elapsed time for sample reduction) = 25.9 minutes

Let's find the number of periods elapsed (x), let us see:

$T = x*P$

$25.9 = x*10.0$

$25.9 = 10.0\:x$

$10.0\:x = 25.9$

$x = \dfrac{25.9}{10.0}$

$\boxed{x = 2.59}$

Now, let's find the final mass (m) of this isotope after the elapsed time, let's see:

$m = \dfrac{m_o}{2^x}$

$m = \dfrac{53.3}{2^{2.59}}$

$m \approx \dfrac{53.3}{6.021}$

$\boxed{\boxed{m \approx 8.85\:mg}}\end{array}}\qquad\checkmark$

I Hope this helps, greetings ... DexteR! =)

3 0

3 years ago