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enot [183]
3 years ago
15

What is the correct answer?

Chemistry
1 answer:
densk [106]3 years ago
8 0

Answer:

I think the answer is (a)-repeat the experiment using a larger sample size

I hope I can answer your question!

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Please help!!! ASAP
bekas [8.4K]

Na 2Co3

1*23=23. 2*12=24. 6*16=96

23+24+96=143

(23*100)/143. (24*100)/143. (96*100)/143

=16%. =16.7%. =67.1%

5 0
3 years ago
Does your always work ?
yaroslaw [1]

Answer:

Explanation:

Huh

8 0
3 years ago
Read 2 more answers
The Thompson analogy titled "The Carpet-Seed Children Analogy" attempts to deal with the issue of failed ____________________(A)
vazorg [7]

Answer: (D) contraception

Explanation:

8 0
3 years ago
Which of these elements has an atom with the most stable outer electron configuration? * Cl Ca Ne Na
SashulF [63]

Answer:

Neon (Ne) has the most stable outer electron configuration because the outer electron is completely filled and it has octet structure

Explanation:

The configuration of these elements is as follows;

Cl₁₇ = 2, 8,7 (the outer electron is 7)

Ca₂₀ = 2,8,8,2 (the outer electron is 2)

Ne₁₀ = 2,8 (the outer electron is 8)

Na₁₁ = 2,8,1 (the outer electron is 1)

Based on the outer electron value above, Neon (Ne) has the most stable outer electron configuration because the outer electron is completely filled and it has octet structure.

6 0
3 years ago
Cd(s)+2HCI(aq)---- H2(g)+CdCl2(aq). what volume in liters of 0.81m HCI solution would be needed to fully react with 32.71g Cd. a
BigorU [14]

Answer:

0.718L of 0.81M HCl are required

Explanation:

Based on the reaction:

Cd(s)+2HCI(aq) → H2(g)+CdCl2(aq)

<em>1 mol of Cd reacts with 2 moles of HCl</em>

<em />

To solve this question we must, as first, find the moles of Cd. With the moles of Cd we can find the moles of HCl needed to react completely with the Cd. With the moles and the molarity we can find the volume:

<em>Moles Cd -Molar mass: 112.411g/mol-:</em>

32.71g * (1mol / 112.411g) = 0.2910 moles Cd

<em>Moles HCl:</em>

0.2910 moles Cd * (2 moles HCl / 1mol Cd) =

0.5820 moles HCl

<em>Volume:</em>

0.5820 moles HCl * (1L / 0.81moles) =

<h3>0.718L of 0.81M HCl are required</h3>
6 0
3 years ago
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