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2 years ago

Identify the major ions present in an aqueous lioh solution

Chemistry

2 answers:

irakobra [83]2 years ago

7 0

Answer: The major ions present in aqueous LiOH solution is lithium ions and hydroxide ions.

Explanation:

Ionization reaction is defined as the reaction in which an ionic compound dissociates into its ions when dissolved in aqueous solution.

The chemical equation for the ionization of LiOH solution follows:

$LiOH(aq.)\rightarrow Li^+(aq.)+OH^-(aq.)$

By Stoichiometry of the reaction:

1 mole of lithium hydroxide produces 1 mole of lithium ions and 1 mole of hydroxide ions

Hence, the major ions present in aqueous LiOH solution is lithium ions and hydroxide ions.

Olegator [25]2 years ago

6 0

When you dissolve an ionic compound into water, the have a tendency to separate from each other. They're still chemically the samething.

LiOH is an ionic compound. Lithium is positive and "borrows" the hydroxide's negative charge to be neutral & vice-versa. When LiOH is dissolved in water the Lithium and the hydroxide separate into their respective forms, also known as ions.

So, LiOH dissolves to become these ions in solution= Li+ and OH-
(the plus and minus represent their charges).

Hope that helps!

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natta225 [31]

Answer: The true statement is iron can reduce $Au^+(aq)$ to gold metal

Explanation:

Single displacement reaction is defined as the reaction in which more reactive element displaces a less reactive element from its chemical reaction.

The reactivity of metal is determined by a series known as reactivity series. The metals lying above in the series are more reactive than the metals which lie below in the series.

$A+BC\rightarrow AC+B$

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We are given:

Iron can reduce copper, silver can reduce gold, sodium can reduce iron and copper can reduce silver metal.

The increasing order of reactivity thus follows:

$Au$

where, sodium is most reactive and gold is least reactive

For the given options:

Option 1: Copper cannot easily reduce sodium ion to sodium metal because it is less reactive.

$Cu(s)+Na^+(aq.)\rightarrow \text{ No reaction}$

Option 2: Iron cant easily reduce gold ion to gold metal because it is more reactive.

$Fe(s)+3Au^+(aq.)\rightarrow Fe^{3+}(aq.)+3Au(s)$

Option 3: Silver cannot easily reduce iron ion to iron metal because it is less reactive.

$Ag(s)+Fe^{3+}(aq.)\rightarrow \text{ No reaction}$

Hence, the true statement is iron can reduce $Au^+(aq)$ to gold metal

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