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Neko [114]
3 years ago
5

Identify the major ions present in an aqueous lioh solution

Chemistry
2 answers:
irakobra [83]3 years ago
7 0

<u>Answer:</u> The major ions present in aqueous LiOH solution is lithium ions and hydroxide ions.

<u>Explanation:</u>

Ionization reaction is defined as the reaction in which an ionic compound dissociates into its ions when dissolved in aqueous solution.

The chemical equation for the ionization of LiOH solution follows:

LiOH(aq.)\rightarrow Li^+(aq.)+OH^-(aq.)

By Stoichiometry of the reaction:

1 mole of lithium hydroxide produces 1 mole of lithium ions and 1 mole of hydroxide ions

Hence, the major ions present in aqueous LiOH solution is lithium ions and hydroxide ions.

Olegator [25]3 years ago
6 0
When you dissolve an ionic compound into water, the have a tendency to separate from each other. They're still chemically the samething.

LiOH is an ionic compound. Lithium is positive and "borrows" the hydroxide's negative charge to be neutral & vice-versa. When LiOH is dissolved in water the Lithium and the hydroxide separate into their respective forms, also known as ions.

So, LiOH dissolves to become these ions in solution= Li+ and OH-
(the plus and minus represent their charges).

Hope that helps!
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7 0
3 years ago
Read 2 more answers
Given:
bulgar [2K]

Answer:

The combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy

Explanation:

Given;

CH₄ + 2O₂ → CO₂ + 2H₂O, ΔH = -890 kJ/mol

From the combustion reaction above, it can be observed that;

1 mole of methane (CH₄) released 890 kilojoules of energy.

Now, we convert 59.7 grams of methane to moles

CH₄ = 12 + (1x4) = 16 g/mol

59.7 g of CH₄ = \frac{59.7}{16} = 3.73125 \ moles

1 mole of methane (CH₄) released 890 kilojoules of energy

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= 3.73125 moles x  -890 kJ/mol

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5 0
3 years ago
How many atoms are in 578g Na
borishaifa [10]

1.51 x 10²⁵atoms

Explanation:

Given parameters:

Mass of Na = 578g

Unknown:

Number of atoms = ?

Solution:

 To find the number of atoms, we must first find the number of moles the given mass contains.

  Number of moles  = \frac{mass}{molar mass}

   molar mass of Na = 23g

 Number of moles =  \frac{578}{23} =  25.13moles

   1 mole of a substance = 6.02 x 10²³atoms

    25.13 mole of Na = 25.13 x  6.02 x 10²³atoms

 This gives  1.51 x 10²⁵atoms of Na

Learn more:

Avogadro's constant brainly.com/question/2746374

#learnwithBrainly

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