Answer:
(1) 820
(2) 1920
Step-by-step explanation:
(1) solving 20 x 41, using associative property.
20 * 41 = (2 x 10) x 41 = 2 x (10 x 41)
= 20 x 41 = 2 x 410
= 820 = 820
(2) distribute 32 as 30 + 2 and solve.
60 x 32
= 60 x (30 + 2) = 60(30) + 60(2)
= 1800 + 120
= 1920
If a polynomial has more than one variable, then thedegree<span> of that </span>monomial<span> is the sum of the exponents of those variables. In this polynomial, 24xyz, the</span>degree<span> is 3 because the sum of </span>degrees<span> of x, y and z is 1 + 1 + 1 = 3. hope this helps :)</span>
Answer:
10,000 :)
Step-by-step explanation:
5,089 rounded =5,000
4,722 rounded= 5,000
= 10,000
Answer : $3403.53
Detailed Solution:
<span>principal was 10,675
interest rate was 4.75% per year compounded annually.
additional $939.25 was paid in service charges.
payment on the principal plus interest is shown below:
pv = 10675
i = .0475/12 = .0039583333... per month.
n = 9 * 12 = 108 months.
fv = 0
pmt = 121.6635... per month
total finance charge would be (108 * 121.6635... + 939.25 - 10675).
that equals to 13139.66 + 939.25 - 10675 = 3403.91
</span>
Answer:
Number of cheaper dresses sold is 35
Number of expensive dresses sold is 15
Step-by-step explanation:
Given:
Cost of cheaper dresses = $90
Cost of expensive dresses = $140
Total cost of the dresses = $5250
To Find:
Number of cheaper dress = ?
Number of expensive dress = ?
Solution:
Let
The number of cheaper dresses be x
The number of expensive dresses be y
(Number of cheaper dresses X cost of cheap dress) + (Number of Expensive dresses X cost of expensive dress) = $5250
= $5250
It is given that the 20 more of the cheaper dresses than the expensive dresses is sold
So,
number of cheaper dress = 20 + number of expensive dress
x = 20 + y---------------------------------------(1)
y = 15
Substituting y in (1)
x = 20 +15
x= 35
