Question

How much energy must a refrigerator absorb from 225 g of water so that the temperature of the water will drop from 35°c to 5°c

Answer 1

Heat energy required to change the temperature is given by

$Q = ms\Delta T$

here we know that

$m = 225 g = 0.225 kg$

$s = 4186 J/kg C$

$T_i = 5 ^0C$

$T_f = 35 ^0C$

now from above formula we will have

$Q = (0.225 kg)(4186 J/kg C) (35 - 5)$

$Q = 28255.5 J$

So it will remove 28255.5 J heat from the water