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2 years ago

For the question below which equation should be used?

Physics

1 answer:

velikii [3]2 years ago

4 0

Answer:

Equation 2

Explanation:

Initial velocity ( Vo ) = 20 m/s

Acceleration ( a ) = 1.1 m/s^2

Distance ( d ) = 55 m

Final velocity ( Vi ) can be found using equation 2

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At a maximum level of loudness, the power output of a 75-piece orchestra radiated as sound is 72.0 W. What is the intensity of t

FrozenT [24]

Answer:

<em> The intensity would be 0.01432 W/</em> $m^{2}$ <em></em>

Explanation:

The sound intensity is the power that is transmitted by a sound wave per unit area.

Given that

Power output P of the 75-piece orchestra = 72.0 W

The listener's distance r = 20.0 m

The intensity of sound waves (I) can be obtained with the expression below;

I = P/A .............. 1

where P is the power

A is the area, in this case, at the distance r the sound is radiated through a sphere.

A = area of a sphere = 4π $r^{2}$

putting it into equation 1, the intensity would be;

I = P/ 4π $r^{2}$

Substituting our values we have;

I = 72.0 W / 4 π $20^{2}$ $m^{2}$

I = 0.01432 W/ $m^{2}$

Therefore the intensity would be 0.01432 W/ $m^{2}$

3 0

3 years ago

1. What is the value of the acceleration that the car experiences? 2. What is the value of the change in velocity that the car e

tankabanditka [31]

Answer:

All the answers are solved and explained below.

Explanation:

Note: This questions lacks the initial and most necessary data to answer these following questions. I have found a related question. I will be considering that question to carry out the answers.

Question: A car with a mass of 1000 kg is at rest at a spotlight. when the light turns green, it is pushed by a net force of 2000 N for 10 s. (This was the information missing in this question).

Data Given:

m = 1000 kg

F = 2000N

t = 10s

Q1 Solution:

Acceleration = a = ?

F = ma

a = F/m

a = 2000/ 1000

a = 2 $m/s^{2}$

Q2: Solution:

Change in velocity = Δv = ?

acceleration = change in velocity / time

a = Δv/t

Δv = axt

Δv = 2 x 10

Δv = 20 m/s

Q3: Solution:

Impulse = I = ?

Impulse = Force x time

I = 2000 x 10

I = 20000 Ns

Q4: Solution:

Change in Momentum = Δp = ?

Δp = mΔv

Δp = 1000 x 20

Δp = 20000 Kgm/s

Q5: Solution:

Final velocity of the car at the end of 10 seconds = vf = ?

Δp = m x Δv

Δp = m x (vf-vi)

Δp = 1000 x (vf - 0 )

20000 = 1000 x vf

vf = 20000/1000

vf = 20 m/s

Q6: Solution:

Change in momentum the car experiences as it continues at this velocity?

Δp = ?

Δp = mΔv

Δp = m x (0)

Δp = 0

Q7: Solution:

Impulse = Change in momentum

Impulse = Δp

Implulse = 0

Q8: Solution:

Change in momentum = Δp = mΔv

Δp = m(vf-vi)

Δp = 1000 x (0-20)

Δp = -20000 kgm/s

Q9: Solution:

Impulse = Δp

Impulse = -20000 Ns

Q10: Solution:

Impulse = ?

Impulse = F x t

F = impulse/t

F = -20000/4s

F = -5000 N

Q11: Solution:

F = ma

a = ?

a = F/m

a = -5000/1000

a = -5 $m/s^{2}$

6 0

3 years ago

After a collision, the y-component of momentum of a car is 4.50 meters/second, and the x-component of its momentum is 9.80 meter

Natalka [10]

The components are at a right angle so the resultant is R^2 = 4.50^2 + 9.80^2 R = 10.78 or 10.8

Hope this helps!!
~Lena~

5 0

3 years ago

When a .22-caliber rifle is fired, the expanding gas from the burning gunpowder creates a pressure behind the bullet. This press

mario62 [17]

Answer:

$1.18454\times 10^{-19}\ Pa$

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

m = Mass of bullet = $2.6\times 10^{23}\ kg$

r = Radius of barrel = $2.8\times 10^{23}\ m$

$v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{370^2-0^2}{2\times 0.61}\\\Rightarrow a=112213.11475\ m/s^2$

Pressure is given by

$P=\dfrac{F}{A}\\\Rightarrow P=\dfrac{ma}{\pi r^2}\\\Rightarrow P=\dfrac{2.6\times 10^{23}\times 112213.11475}{\pi (2.8\times 10^{23})^2}\\\Rightarrow P=1.18454\times 10^{-19}\ Pa$

The pressure of the expanding gas is $1.18454\times 10^{-19}\ Pa$

7 0

3 years ago

Can water and wind change the shape of a mountain

Art [367]

Answer:

Yes, through erosion.

Explanation:

Water, wind, and ice shape earths surface. Water, wind, & ice move sediment to another area this process is called erosion.

Mark me brainliest, hope this helps

4 0

3 years ago