Question

Dx= 7.14m and Dy = -7.55m What is the direction and magnitude of the vector

Answer 1

The Magnitude of the Vector is 10.39m and the direction of the vector is - 46.7°.

Explanation:

GIven dx=7.14m and dy= -7.55m,

The Magnitude of the Vector=$\sqrt{dy^{2} +dx^{2} }$

Magnitude d= $\sqrt{(7.14)^{2} +(-7.55)^{2} }$ .

                  d=$\sqrt{50.97+57}$

                  d=$\sqrt{107.98}$

                  d= 10.39m.

Direction Ф = $tan^{-1}$$\frac{dy}{dx}$

                      =$tan^{-1}$ $\frac{-7.55}{7.14}$      

                      = $tan^{-1}$(-1.06)

                Ф    = - 46.7°.