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stellarik [79]
3 years ago
6

Find a polynomial function of degree 3 such that f(10)=17 and the zeros of f are 0, 5 and 8

Mathematics
1 answer:
fomenos3 years ago
3 0

Step-by-step explanation:

Since f(0) = f(5) = f(8) = 0, we have f(x) = Ax(x - 5)(x - 8), where A is a real constant.

We know that f(10) = 17.

=> A(10)(10 - 5)(10 - 8) = 17

=> A(10)(5)(2) = 17

=> 100A = 17, A = 0.17.

Hence the answer is f(x) = 0.17x(x - 5)(x - 8).

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Answer:

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Step-by-step explanation:

we have the ratio

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To write as percent, multiply the ratio by 100

so

\frac{41}{100}*100=41*100/100=41\%

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Danny had 20 minutes to do a three-problem quiz. He spent 9 1/4 minutes on question A and 5 4/5 minutes on question B. How much
Travka [436]

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Step-by-step explanation:

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telo118 [61]

Step-by-step explanation:

Slope, which is the same as gradient, is equal to

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<h3>slope =  \frac{change \: in \: y}{change \: in \: x}</h3>

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In (-12,-12),let the first -12 be <em>x1</em><em> </em>and the second one be <em>y1</em>

Same goes for the (9,-9), let 9 be <em>X2</em><em> </em>and -9l be <em>y2</em>

<em>slope =  \frac{y2 - y1}{x2 - x1}</em>

<em>=  - \frac{ - 9 -  - 12}{9 - 12}</em>

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