Question

An airplane is at an elevation of 35,000 ft when it its approach to an airport. Its angle of descent is 6°.

Answer 1

Let the ground distance be x
tan6=35000÷x
x=333000 ft (corr. to 3 sig. fig.)

Let the air distance be y
sin6=35000÷y
y=335000 ft (corr. to 3 sig.fig.)