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svet-max [94.6K]
3 years ago
13

An airplane is at an elevation of 35,000 ft when it its approach to an airport. Its angle of descent is 6°.

Mathematics
1 answer:
Amanda [17]3 years ago
7 0
Let the ground distance be x
tan6=35000÷x
x=333000 ft (corr. to 3 sig. fig.)

Let the air distance be y
sin6=35000÷y
y=335000 ft (corr. to 3 sig.fig.)
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