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Vikentia [17]
4 years ago
10

A town has a​ merchant, a​ baker, and a farmer. To produce​ $1 worth of​ output, the merchant requires ​$0.15 worth of baked goo

ds and ​$0.35 worth of the​ farmer's products. To produce​ $1 worth of​ output, the baker requires ​$0.45 worth of the​ merchant's goods, ​$0.20 worth of his own​ goods, and ​$0.35 worth of the​ farmer's goods. To produce​ $1 worth of​ output, the farmer requires ​$0.25 worth of the​ merchant's goods, ​$0.25 worth of baked​ goods, and ​$0.30 worth of his own products. How much should the​ merchant, baker, and farmer produce to meet a demand for ​$18 comma 000 worth of output from the​ merchant, ​$11 comma 000 worth of output from the​ baker, and ​$12 comma 000 worth of output from the​ farmer?
Mathematics
1 answer:
valentina_108 [34]4 years ago
6 0

Answer:

Merchant: $7950

Baker: $7900

Farmer: $13750

Step-by-step explanation:

To produce $18000 worth of output from merchant we would need

- $18000*0.15 = $2700 worth of product from the baker

- $18000*0.35 = $6300 worth of product form the farmer

To produce $11000 worth of output from the baker we would need

- $11000*0.45 = $4950 worth of product from the merchant

- $11000*0.2 = $2200 worth of product from himself

- $11000*0.35 = $3850 worth of product form the farmer

To produce $12000 worth of output from the farmer we would need

- $12000*0.25 = $3000 worth of product from the merchant

- $12000*0.25 = $3000 worth of product from the baker

- $12000*0.3 = $3600 worth of product form the himself

In total:

The merchant would need to produce: $4950 + $3000 = $7950

The baker would need to produce: $2700 + $2200 + $3000 = $7900

The farmer would need to produce: $6300 + $3850 + $3600 = $13750

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I just did one of these. I guessed that normal form is


x \cos \phi + y \sin \phi -  p = 0


Here' that's


x (\sqrt{3}/2) + y (1/2) - 10 = 0


\sqrt{3} x + y - 20 = 0


Choice b




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3 years ago
Mr. Garcia is spreading mulch in his yard he spreads 3 square yards and 40 minutes how many square yards can he mulch in 1 hour
Verdich [7]

Answer:

Step-by-step explanation:

3 over 2/3 → 3/1 divided by 2/3  → 3/1  x 3/2 (do keep change flip)

once you multiply you'll get 9/2.

4 0
3 years ago
Larissa has 4 ? cups of flour. She is making cookies using a recipe that calls for 2 ? cups of flour. After baking the cookies,
Scorpion4ik [409]

Answer:

2 cups of flour

Step-by-step explanation:

4-2 = 2

4 0
4 years ago
If the value of point is 3/2 and |Q| is 5/4 then the greatest value of P+Q is
Ne4ueva [31]

Answer:

11/4 or 2 3/4

Step-by-step explanation:

3/2+5/4

(3x4) + (5x2)=2x4

=22/8

=22÷2

=8÷2

=11/4 or 2 3/4

5 0
3 years ago
There are three different hoses used to fill a pool: hose x, hose y, and hose z. Hose x can fill the pool in a days, hose y in b
WARRIOR [948]

Answer:

C) I and III only

Step-by-step explanation:

Let full pool is denoted by O

Days Hose x takes to fill pool O = a

Pool filled in one day x = O/a

Days Hose y takes to fill pool O = b

Pool filled in one day y = O/b

Days Hose z takes to fill pool O = c

Pool filled in one day z = O/c

It is given that

                         a>b>c

a>b>c>d\\\implies x

Days if if x+y+z fill the pool together = d

1 day if x+y+z fill the pool together =O(\frac{1}{a}+\frac{1}{b}+\frac{1}{c})=\frac{O}{d}---(1)

I) d < c

d are days when hose x, y, z are used together where as c are days when only z is used so number of days when three hoses are used together must be less than c when only z hose is used. So d < c

III) \frac{c}{3}

Using (1)

\frac{bc+ac+ab}{abc}=\frac{1}{d}\\\\d=\frac{abc}{ab+bc+ca}\\\\As\quad(a>b>c)\\(ab+bc+ca)\frac{abc}{3ab}\\\\d>\frac{c}{3}

Similarly

\frac{bc+ac+ab}{abc}=\frac{1}{d}\\\\d=\frac{abc}{ab+bc+ca}\\\\As\quad a>b>c\\(ab+bc+ca)>3bc\\\\d=\frac{abc}{ab+bc+ca}

So,

\frac{c}{3}

3 0
3 years ago
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