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Lady_Fox [76]
3 years ago
6

What did the inventor of the 10 ton truck so often say

Mathematics
2 answers:
ollegr [7]3 years ago
7 0

Answer:

This is an equation in which we have to find the slope of the line. We are supposed to draw the line for the two given points.

Step-by-step explanation:

The equation and the graph are solved as:

  • <u>For graph One</u>: B=(4,4)(1,2)  for that m= 2/3. E=(2,0)(-4,4), for this m=-2/3. O=(1,-3)(-3,-4),m=1/4.
  • for Second graph: I=(-1,-3)(2,3), m=2. E=(-4,-3)(-2,-1), m=-2. O=(-3,0)(-1,5),m=5/2.
  • for the third graph:E=(0,2)(5,-1),m=-3/5. D=(5,6)(2,-1), m=7/3.L=(-5,2)(0,-3),m=-1.
  • for the fourth graph: D=(0,0)(2,-6),m=-3. G=(4,5)(-2,4),m=1/6. S=(2,-3)(-5,-3), m=0.

Now the Graphical data and the results are attached to the answer, given hope it helps out.

Lunna [17]3 years ago
6 0
Here is the answer to the given riddle above. What the inventor of the 10 ton truck so often say is that "Diesel Be Good". This is actually a riddle in math that you have to solve with the corresponding letters. Hope this is the answer that you are looking for.
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Step-by-step explanation:

∫ (sec x − tan x) dx

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ln(sec x + tan x) + ln(cos x) + C

6 0
3 years ago
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kicyunya [14]

Answer:

none above

Step-by-step explanation:

4 0
3 years ago
D(x)=(x^2-12x+20)/(3x)
krok68 [10]

Answers:

Vertical asymptote: x = 0

Horizontal asymptote: None

Slant asymptote: (1/3)x - 4

<u>Explanation:</u>

d(x) = \frac{x^{2}-12x+20}{3x}

      = \frac{(x-2)(x - 10)}{3x}

Discontinuities: (terms that cancel out from numerator and denominator):

Nothing cancels so there are NO discontinuities.

Vertical asymptote (denominator cannot equal zero):

3x ≠ 0  

<u>÷3</u>   <u>÷3 </u>

x ≠ 0

So asymptote is to be drawn at x = 0

Horizontal asymptote (evaluate degree of numerator and denominator):

degree of numerator (2) > degree of denominator (1)

so there is NO horizontal asymptote but slant (oblique) must be calculated.

Slant (Oblique) Asymptote (divide numerator by denominator):

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  •    3x)    x² - 12x + 20
  •             <u>x²        </u>
  •                  -12x
  •                  <u>-12x         </u>
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So, slant asymptote is to be drawn at (1/3)x - 4



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