All categories

3 years ago

A $1500 loan has an annual interest rate of

Mathematics

1 answer:

Goshia [24]3 years ago

4 0

127.50 = 1,500(0.0425) * x

127.50 = 63.75 * x

x= 127.50/63.75

x=2

You might be interested in

set the equation up for "Eight less than the square of a number is the same as adding the number and four"

TEA [102]

X^2-8 = x+4 is your answer!

5 0

3 years ago

Find the length of UV.

katovenus [111]

7x-8 (2) = 12x+8
14x-16 = 12x+8
-12x -12x
2x-16 = 8
+16 +16
2x = 24

÷2 ÷2
x= 12

UV= 7x-8
UV= 7(12)-8
UV= 84-8
UV= 76

7 0

2 years ago

Jillian ran 40 miles in one week. Her friend Lacey ran 5/8 the distance that Jillian ran.

marishachu [46]

40 / 8 =5. 5 * % = **25 Miles**

8 0

3 years ago

The sum of three numbers $x$ ,$y$, $z$ is 165. When the smallest number $x$ is multiplied by 7, the result is $n$. The value $n$

babymother [125]

You're given

x + y + z = 165

7x = n

n = y - 9

n = 9 + z

and you want to find xyz.

Solve the last three equations for x, y, and z :

7x = n → x = n/7

n = y - 9 → y = n + 9

n = 9 + z → z = n - 9

Substitute x, y, and z into the first equation and solve for n :

n/7 + (n + 9) + (n - 9) = 165

n/7 + 2n = 165

n + 14n = 1155

15n = 1155

n = 77

Now solve for x, y, and z :

x = 77/7 = 11

y = 77 + 9 = 86

z = 77 - 9 = 68

Then the product is

xyz = 11 • 86 • 68 = 64,328

6 0

2 years ago

the letters of the word independent are written on individual card and the cards are put into a box a card is selected and then

puteri [66]

Answer:

The probability of obtaining the letter p twice is 1/121

Step-by-step explanation:

Probability of Recurring Events

There are 11 letters in the word 'independent', one of which is the letter 'p'.

When those letters are written on individual cards and they are put into a box, there are 11 different choices to pick at random.

This means the individual probability of getting a 'p' is:

$\displaystyle P_1=\frac{1}{11}$

The card is reinserted into the box, leaving the sample space unaltered, thus the second card has the same probability:

$\displaystyle P_2=\frac{1}{11}$

We'll use the multiplication rule. Just multiply the probability of the first event by the second.

$\displaystyle P=P_1*P_2=\frac{1}{11}*\frac{1}{11}$

$\displaystyle P=\frac{1}{121}$

The probability of obtaining the letter p twice is 1/121

6 0

2 years ago