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Svetlanka [38]
3 years ago
10

How many thousands are in 327,412?

Mathematics
1 answer:
Alexxandr [17]3 years ago
8 0

Answer:

327

Step-by-step explanation:

In the thousands cateragory of the number lies the numbers 327 giving you your answer

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Find the exact value of cos(a+b) if cos a=-1/3 and cos b=-1/4 if the terminal side if a lies in quadrant 3 and the terminal side
maria [59]

Answer:

cos(a + b) = \frac{1}{12}(1-2\sqrt{30})

Step-by-step explanation:

cos(a + b) = cos(a).cos(b) - sin(a).sin(b) [Identity]

cos(a) = -\frac{1}{3}

cos(b) = -\frac{1}{4}

Since, terminal side of angle 'a' lies in quadrant 3, sine of angle 'a' will be negative.

sin(a) = -\sqrt{1-(-\frac{1}{3})^2} [Since, sin(a) = \sqrt{(1-\text{cos}^2a)}]

         = -\sqrt{\frac{8}{9}}

         = -\frac{2\sqrt{2}}{3}

Similarly, terminal side of angle 'b' lies in quadrant 2, sine of angle 'b' will be  negative.

sin(b) = -\sqrt{1-(-\frac{1}{4})^2}

         = -\sqrt{\frac{15}{16}}

         = -\frac{\sqrt{15}}{4}

By substituting these values in the identity,

cos(a + b) = (-\frac{1}{3})(-\frac{1}{4})-(-\frac{2\sqrt{2}}{3})(-\frac{\sqrt{15}}{4})

                = \frac{1}{12}-\frac{\sqrt{120}}{12}

                = \frac{1}{12}(1-\sqrt{120})

                = \frac{1}{12}(1-2\sqrt{30})

Therefore, cos(a + b) = \frac{1}{12}(1-2\sqrt{30})

5 0
3 years ago
42 divided by 4 and 67 divided by8
Bezzdna [24]
10.5 and 8.4 ......................,,,,,
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3 years ago
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The sum of 27 and seven times a number is 125. Find the number.
zysi [14]
The number is 14

Here's the solution:

Let the number be x

According to the question,

27+7x=125

//Subtract 27 from both the sides

7x=125-27

7x=98

//divide both the sides by 7

x=98/7

x=14
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3 years ago
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F(x)=x^2. What is g(x)?
Nina [5.8K]

Answer:

C

Step-by-step explanation:

I'm super sorry if I get this wrong you don't have to choose C I feel like I'm wrong but have a nice day

4 0
3 years ago
Rajan climbed to a height of 10 ft from the bottom of a climbing wall. He then climbed up an additional 5 ft. What must he do to
max2010maxim [7]
I'm assuming this is a Pythagorean theorem problem. If so the answer would be √125
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