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lbvjy [14]
3 years ago
10

Which of the following would cause a physical change in a bar of steel?

Chemistry
2 answers:
Anika [276]3 years ago
3 0
B. Hammering it into a new shape.

Hope this helps! Good luck! :)
S_A_V [24]3 years ago
3 0
B hammering it into a new shape
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What’s a conjugative Bas of OH-
LiRa [457]

Answer:

the answer is O²- hopefully

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2 years ago
When a 4.2 gram sample of mercury (Il) oxide, HgO is decomposed into its elements by •
Usimov [2.4K]

Hg = (3.2 : 4.2) x 100% = 76.19%

O = (1 : 4.2) x 100% = 23.81%

7 0
2 years ago
Which observation would best support that the bond present was a covalent bond?
DIA [1.3K]

Answer:

A covalent bond is present between two non-metals that share electrons in their molecular structure.

Explanation:

Examples of covalent bonds may be between carbon dioxide or water. And there may be three types of covalent bonds such as ionic, covalent and polar. In the first type, there is a transfer of an electron resulting in a gain for one of the atoms. In the second type, there is a sharing of electrons between the atoms. The third type is characterized by a difference in electronegativity between atoms.

4 0
2 years ago
The muscles of the body are part of the muscular system but would not operate without the _______ system providing the impulses
MatroZZZ [7]

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The nervous system

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5 0
3 years ago
Methanol, ethanol, and n-propanol are three common alcohols. When 1.00 g of n-propanol (C3H7OH)is burned in air, -33.4 kJ of hea
Inga [223]

Answer : The heat of combustion of n-propanol is 0.554 kJ/mol

Explanation :

First we have to calculate the moles of n-propanol.

\text{Moles of n-propanol}=\frac{\text{Mass of n-propanol}}{\text{Molar mass of n-propanol}}

Molar mass of n-propanol = 60.09 g/mole

\text{Moles of n-propanol}=\frac{1.00g}{60.09g/mole}=0.0166mole

Now we have to calculate the heat of combustion of n-propanol.

As, 0.0166 mole of n-propanol liberated heat of combustion = -33.4 kJ

So, 1 mole of n-propanol liberated heat of combustion = 0.0166 × (-33.4 kJ)

                                                                                           = 0.554 kJ/mol

Therefore, the heat of combustion of n-propanol is 0.554 kJ/mol

5 0
2 years ago
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