The free energy change(Gibbs free energy-ΔG)=-8.698 kJ/mol
<h3>Further explanation</h3>
Given
Ratio of the concentrations of the products to the concentrations of the reactants is 22.3
Temperature = 37 C = 310 K
ΔG°=-16.7 kJ/mol
Required
the free energy change
Solution
Ratio of the concentration : equilbrium constant = K = 22.3
We can use Gibbs free energy :
ΔG = ΔG°+ RT ln K
R=8.314 .10⁻³ kJ/mol K
Answer:
atom 2 and 3 or d is should be your answer
Explanation:
.....
Answer:
The mole is the SI unit for amount of a substance.
Explanation:
Just like the dozen and the gross, it is a name that stands for a number. There are therefore 6.02 × 10 23 water molecules in a mole of water molecules.
Hello!
The pressure of the Ideal Gas when the volume is 1,45 L and the temperature is 298 K is
1,82 atm.
To solve this problem we need to apply the
Ideal Gas Law for the initial conditions and the final ones, clearing the equation for the number of moles (n) and the ideal gas constant (R) which remain constant:
Now we match n*R for the initial conditions (1) and the final ones (2), clearing the equation for P₂
Have a nice day!
