Answer:
mass of bike is 100 kg
Explanation:
weight = mass* acceleration due to gravity
w= mg
if g= 9.8 m/s²
then mass= w/g =980/9.8= 100kg
Answer:
B. toward the products
Explanation:
The equilibrium constant of an equilibrium reaction measures relative amounts of the products and the reactants present at equilibrium. It is the ratio of the concentration of the products and the reactants each raised to their stoichiometric coefficients. The concentration of the liquid and the gaseous species does not change and thus is not written in the expression.
Thus, on increasing the concentration of any one of the reactant, the value of equilibrium constant will decrease.
The reaction quotient of an equilibrium reaction measures relative amounts of the products and the reactants present during the course of the reaction at particular point in the time.
Q < Kc , reaction will proceed in forward direction.
Q > Kc , reaction will proceed in backward direction.
Q = Kc , reaction at equilibrium.
<u>Since, given that The equilibrium constant for the reaction is 24. On increasing the concentration of one of the reactant, the reaction quotient will become less than Kc and thus, go in forward direction which means that towards the product.</u>
1. D
2. DR
3. SR
4. DR
5. C
6. SR
7. S
8. D
10. C
Answer:
Option D
Explanation:
For the first statement, the order is:
=> Co < Fe < Zn < Al
For the second statement it is,
=> Ni < Co < Fe
So, combining the order becomes:
=> Ni < Co < Fe < Zn < Al
Answer:
Final temperature is 34.2 °C
Explanation:
Given data:
mass of metal = 125 g
temperature of metal = 93.2 °C
mass of water v= 100 g
temperature of water = 18.3 °C
specific heat of meta is = 0.900 j/g. °C
specific heat of water is = 4.186 j/g. °C
final temperature of water and metal = ?
Solution:
Q = m . c . ΔT
ΔT = T2-T1
now we will put the values in equation
Q1 = m . c . ΔT
Q1 = 125 g. 0.900 j/g. °C .93.2°C - T2
Q1 = 112.5 (93.2°C - T2)
Q1 =10,485 - 112.5T2
Q2 = m . c . ΔT
Q2 = 100 . 4.186. (T2- 18.3)
Q2 = 418.6 . (T2- 18.3)
Q2 = 418.6T2 - 7660.38
10,485 - 112.5T2 = 418.6T2 - 7660.38
10,485 + 7660.38 = 418.6T2+ 112.5T2
18145.38 = 531.1 T2
T2 = 18145.38/531.1
T2 = 34.2 °C
