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Leona [35]
3 years ago
15

Can you choose any two distinct points on a line to calculate the slope? True or False?

Mathematics
2 answers:
marin [14]3 years ago
4 0
True, u can choose any two distinct points on a line to calculate the slope
telo118 [61]3 years ago
3 0

Answer: True, we can choose any two distinct points on a line to calculate the slope.

Step-by-step explanation:

The slope of a line tells the rate of change of the dependent variable with respect to change in the independent variable.

For a line, the rate of change is constant.

Therefore, the slope of a line is constant.

Since, for any any two points, there is always a unique line passing through it it.

So, we can choose any two distinct points  from the line, it doesn't matter with the answer, it will remain constant.

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Write the equation of a line that contains (2,−2) and perpendicular to another line with slope −1.
Reika [66]

Answer:

y = x - 4

Step-by-step explanation:

Perpendicular slope = 1

y + 2 = 1 (x - 2)

y + 2 = x - 2

y = x - 4

3 0
2 years ago
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How do you solve these equations? I don't want you to answer all of them, just tell me how to solve each type of equation on the
miss Akunina [59]

Answer:

8. Identify the common denominator; express each fraction using that denominator; combine the numerators of those rewritten fractions and express the result over the common denominator. Factor out any common factors from numerator and denominator in your result. (It's exactly the same set of instructions that apply for completely numerical fractions.)

9. As with numerical fractions, multiply the numerator by the inverse of the denominator; cancel common factors from numerator and denominator.

10. The method often recommended is to multiply the equation by a common denominator to eliminate the fractions. Then solve in the usual way. Check all answers. If one of the answers makes your multiplier (common denominator) be zero, it is extraneous. (10a cannot have extraneous solutions; 10b might)

Step-by-step explanation:

For a couple of these, it is helpful to remember that (a-b) = -(b-a).

<h3>8d.</h3>

\dfrac{5}{x+2}+\dfrac{25-x}{x^2-3x-10}=\dfrac{5(x-5)}{(x+2)(x-5)}+\dfrac{25-x}{(x+2)(x-5)}\\\\=\dfrac{5x-25+25-x}{(x+2)(x-5)}=\dfrac{4x}{x^2-3x-10}

___

<h3>9b.</h3>

\displaystyle\frac{\left(\frac{x}{x-2}\right)}{\left(\frac{2x}{2-x}\right)}=\frac{x}{x-2}\cdot\frac{-(x-2)}{2x}=\frac{-x(x-2)}{2x(x-2)}=-\frac{1}{2}

___

<h3>10b.</h3>

\dfrac{3}{x-1}+\dfrac{6}{x^2-3x+2}=2\\\\\dfrac{3(x-2)}{(x-1)(x-2)}+\dfrac{6}{(x-1)(x-2)}=\dfrac{2(x-1)(x-2)}{(x-1)(x-2)}\\\\3x-6+6=2(x^2-3x+2) \qquad\text{multiply by the denominator}\\\\2x^2-9x+4=0 \qquad\text{subtract 3x}\\\\(2x-1)(x-4)=0 \qquad\text{factor; x=1/2, x=4}

Neither solution makes any denominator be zero, so both are good solutions.

8 0
3 years ago
Two angles form a linear pair. The measure of one angle is 16∘ greater than the measure of the other angle. Find the measure of
Agata [3.3K]

A) Angle 1 + Angle 2 = 180

B) Angle 1 - Angle 2 = 16

Adding both equations:

2 * Angle 1 = 196

Angle 1 = 98

Angle 2 = 82


4 0
3 years ago
4) Ella bought two packs of blackberry juice for $15 and three candy bars from a store. If her total purchase was worth $45, how
lord [1]
One candy bar would be $5 thus 3 bars being $15 plus the $30 in juice which equals $45 :)
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Answer:

It doesnt

Step-by-step explanation:

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3 years ago
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