Question

I need help on this one pls help me

Answer 1

B.) 1.32 miles.

Use the distance formula to help you find how far it is from one point to another. The distance formula is:
$d = \sqrt{(x _{2} - x _{1}){}^{2} + (y _{2} - y _{1}) {}^{2} }$
You will have to use this formula twice.

So first is the distance between his house and the library. The coordinates of the house are (0,0) and the coordinates of the library are (3,4). So in that order, x1=0, x2=3, y1=0, and y2=4. Plug these into the formula and you get:
$d = \sqrt{(3 - 0) {}^{2} + (4 - 0) {}^{2} }$
Simplify that and you get √(9+16), which is equal to √25, or 5. This is your first answer.

Next use the same formula to find the distance between the library and the school. This time x1=3, x2=11, y1=4, and y2=2. Plug thisninto the formula and you get:
$d = \sqrt{(11 - 3) {}^{2} + (2 - 4) {}^{2} }$
Simplify this and you get √(64+4), which is equal to √68, or approximately 8.25.

Add the two distances together, so 5+8.25=13.25, then multiply that by 0.1, since each square is equal to 0.1 miles. You should get 1.32.

Answer 2

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