Answer:
There's two ways to solve this.
Step-by-step explanation:
First way:
Let's divide the width and length by 2.3.
46÷2.3=20
69÷2.3=30
20×30
600 ft²
Second Way:
Let's find the area of the actual room.
46×69
3,174 ft²
Let's find the scale drawing squared.
2.3²=5.29
3,174÷5.29
600 ft²
Answer:
Step-by-step explanation:
38. 450 divided by 12 is 37.5 and you can’t have half of a carton so one carton would be half full
Sometimes a diagram can be helpful. If x is the distance from the house to the parallel side of the fenced plot, then the total length of fence will be x + x + 30 (feet). Jane wants to find x such that this length is 100 (feet).
The appropriate equation is ...
... A. x + x + 30 = 100
Answer:
Solution given:
total female [T]=3+4+6+3=16
n[senior female]=3.
probability the student is a senior given that it's
female:![\frac{n[senior female]}{total [T]}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bn%5Bsenior%20female%5D%7D%7Btotal%20%5BT%5D%7D%20)
:
:
is a probability.
Now percentage::
=18.75=19%
% error= (actual height-measured height)/actual height x100%
=(6-5.23)/6 x100%
=0.77/6 x100%
=12.83%