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4 years ago

Please help me, giving brainliest.

Mathematics

1 answer:

emmainna [20.7K]4 years ago

4 0

I'm not sure what you want but the slope for each graph from left to right is 5, -7/8, -2.

The equation of each graph from left to right in slope intercept form is

y = 5x + 2, y = -7/8x - 11/8, y = -2x + 6.

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Could somebody help.

Marianna [84]

The answer is 4/9.

To find the answer you would need to find the values of x and y. Using the given information you know x/5 is equal to 2/3. Then you would cross multiply and divide in order to fine the value of x, which is 10/3. Doing the same thing to find y, which would be 15/2. Since it’s day the ratio of x and y. You would divide the value of x by y to get your answer of 4/9.

8 0

3 years ago

mestny [16]

Answer:

12... If there is an even ratio between the two, then there is an even amount, so you divide 24 by 2 and you have 12 chocolate and 12 vanilla cupcakes in the Grande box.

Step-by-step explanation:

<em>It izz wat it izzzz!!!</em>

5 0

3 years ago

Read 2 more answers

What are the domain and range of f(x) = 2x - 41?

Darina [25.2K]

The domain of the function is a (-∞, 0) and the range of the function will be f(x) < 0. Then the correct option is C.

<h3>What are domain and range?</h3>

The domain means all the possible values of x and the range means all the possible values of y.

The function is given below.

f(x) = 2x – 41

Then the domain of the function is a (-∞, 0) and the range of the function will be f(x) < 0.

Then the correct option is C.

More about the domain and range link is given below.

brainly.com/question/12208715

#SPJ1

3 0

2 years ago

A ball is thrown from an initial height of 1 meter with an initial upward velocity of 15m/s. The ball's height h (in meters) aft

lakkis [162]

$\bf \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{h}=1+15t-5t^2}\implies \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{6}=1+15t-5t^2}\implies 0=-5+15t-5t^2 \\\\\\ ~~~~~~~~~~~~\textit{using the quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{5}t^2\stackrel{\stackrel{b}{\downarrow }}{-15}t\stackrel{\stackrel{c}{\downarrow }}{+5}=0 \qquad \qquad t= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}$

$\bf t=\cfrac{-(-15)\pm\sqrt{(-15)^2-4(5)(5)}}{2(5)}\implies t=\cfrac{15\pm\sqrt{225-100}}{10} \\\\\\ t=\cfrac{15\pm\sqrt{125}}{10}\implies t=\cfrac{15\pm\sqrt{5^2 \cdot 5}}{10}\implies t=\cfrac{\stackrel{3}{~~\begin{matrix} 15 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\pm ~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\sqrt{5}}{\underset{2}{~~\begin{matrix} 10 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}$

$\bf t=\cfrac{3\pm \sqrt{5}}{2}\implies t= \begin{cases} \frac{3+ \sqrt{5}}{2} \approx 2.618\\\\ \frac{3- \sqrt{5}}{2}\approx 0.382 \end{cases}$

8 0

3 years ago

Suzanna wants to fill a cylindrical vase 2/3 of the way with water before placing her flowers in it. What is the approximate vol

FrozenT [24]

$\bf \textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=5\\ h=14 \end{cases}\implies V=\pi (5)^2(14)\implies V=350\pi \\\\\\ \stackrel{\textit{and }\frac{2}{3}\textit{ of that whole volume is}}{\cfrac{2}{3}(350\pi )}\implies \cfrac{700\pi }{3}\implies \stackrel{\textit{using }\pi =3.14}{\cfrac{2198}{3}}\implies \stackrel{\textit{rounded up}}{732.7}$

6 0

3 years ago