Question

A student prepares a solution of sodium chloride by dissolving 116.9 g of NaCl into enough water to make 1.00 L of solution. How would the student properly label this solution? A. 2.00 M NaCl B. 116.9 g/ L NaCl C. 116.9 M NaCl D. 2.00 M/L NaCl

Answer 1

Answer: The molarity of the solution is 2.00 M

Explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n}{V_s}$

where,

n = moles of solute

$V_s$ = volume of solution in L = 1.00 L

moles of solute =$\frac{\text {given mass}}{\text {molar mass}}=\frac{116.9g}{58.5g/mol}=2.00moles$

$Molarity=\frac{2.00mol}{1.00L}=2.00M$

Thus the molarity of the solution is 2.00 M