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Gnoma [55]
3 years ago
15

Give two real life applications of chromatography

Chemistry
2 answers:
AleksAgata [21]3 years ago
7 0

Answer:

1. Additive detection

2. Crime scene testing

koban [17]3 years ago
4 0

Answer:

Food testing.

Beverage testing.

Drug testing.

Forensic testing.

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A 3.00-L flask is filled with gaseous ammonia, NH3. The gas pressure measured at 27.0 ∘C is 2.55 atm . Assuming ideal gas behavi
Whitepunk [10]

Answer : The mass of ammonia present in the flask in three significant figures are, 5.28 grams.

Solution :

Using ideal gas equation,

PV=nRT\\\\PV=\frac{w}{M}\times RT

where,

n = number of moles of gas

w = mass of ammonia gas  = ?

P = pressure of the ammonia gas = 2.55 atm

T = temperature of the ammonia gas = 27^oC=273+27=300K

M = molar mass of ammonia gas = 17 g/mole

R = gas constant = 0.0821 L.atm/mole.K

V = volume of ammonia gas = 3.00 L

Now put all the given values in the above equation, we get the mass of ammonia gas.

(2.55atm)\times (3.00L)=\frac{w}{17g/mole}\times (0.0821L.atm/mole.K)\times (300K)

w=5.28g

Therefore, the mass of ammonia present in the flask in three significant figures are, 5.28 grams.

8 0
4 years ago
Given that E°red = -0.40 V for Cd2+/Cd at 25°C, find E° and E for the concentration cell expressed using shorthand notation belo
tensa zangetsu [6.8K]

From the information in the question, the  E° and E for the cell is 0.00 V and 0.12 V.

Using the Nernst equation;

Ecell =  E°cell - 0.0592/n log Q

We know that  E°cell = 0.00 V since the anode and cathode are both made up of cadmium.

Substituting the given values into the Nernst equation;

Ecell = 0.00 V - 0.0592/2 log (1.0 × 10-5 M/0.100 M)

Ecell =  0.00 V - 0.0296 log(1 × 10^-4)

Ecell = 0.12 V

Learn more: brainly.com/question/8646601

3 0
3 years ago
What has more force? A semi truck traveling at 60mph or a minivan traveling at 60mph?
hodyreva [135]

Answer:

Semi truck

Explanation:

5 0
3 years ago
Read 2 more answers
NH3 + CO2 + H2O → NH4HCO3 Balance this reaction if necessary. A) balanced B) 1, 1, 2, 1 C) 1, 2, 1, 2 D) 1, 2, 2, 2
Julli [10]

Answer:

NH3 + CO2 + H2O -> NH4HCO3

This equation is already balanced

4 0
3 years ago
Read 2 more answers
So you are using the combined gas law
shusha [124]

Answer:

7.22L

Explanation:

At Stp T2 = 273K and P2 is 1 atm

So we have the following data

V1 =10L. P1=650mmHg(0.855atm)

V2 =V2. P2 = 1 atm

T1=50°c (323K) T2 =273K

Hence from the combined gas law

P1xV1 /T1 =P2xV2/T2

0.855x10/323 =1xV2 /273

8.55/323 =V2 /273

V2 = 8.55x273 /323

V2 = 7.226 L

5 0
3 years ago
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