Answer:
CH4 + 2O2 → CO2 + 2H2O Incomplete combustion – carbon monoxide and water. Ex. 2CH4 + 3O2 → 2CO + 4H2O The amount of oxygen present and the temperature determine whether the reaction is complete or incomplete.
Answer:
48 molecules of CO₂
Explanation:
I think you made a mistake in your question. The formula for propane is C₃H₈, not C₃H₃. But, I will give you the answer for both cases.
For C₃H₃:
First you have to balance the equation.
4 C₃H₃ + 15 O₂ ⇒ 12 CO₂ + 6 H₂O
Next, you need to use the mole ratios between C₃H₃ and CO₂ to find the amount of molecules of CO₂ you will produce with the given amount of C₃H₃.
(16 mol's C₃H₃) × (12 mol's CO₂/4 mol's C₃H₃) = 48 mol's CO₂
You will get 48 molecules of CO₂.
For C₃H₈:
Balance the equation.
C₃H₈ + 5 O₂ ⇒ 3 CO₂ + 4 H₂O
Use the mole ratios between C₃H₈ and CO₂.
(16 mol's C₃H₈) × (3 mol's CO₂/1 mol's C₃H₈) = 48 mol's CO₂
You will get 48 molecules of CO₂ for this equation as well.
Acids tend to have a pH of below 7 (which is neutral).
The only option that makes the pH statement above true is A, 6.
So the answer is with no doubt, A. 6
Data:
Q = 402.7 J → releases → Q = - 402.7 J
m = 16.25 g
T initial = 54 ºC
adopting: c = 4.184J/g/°C
ΔT (T final - T initial) = ?
Solving:
Q = m*c*ΔT
-402.7 = 16.25*4.184*ΔT
-402.7 = 67.99*ΔT
If: ΔT (T final - T initial) = ?
WE LIVE IN THE HOLOCENE EPOCH