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allsm [11]
3 years ago
14

A highway reconstruction project is being undertaken to reduce crash rates. The reconstruction involves a major realignment of t

he highway such that a 60mph design speed is attained. At one point on the highway, a 720-ft equal tangent crest vertical curve exists. Measurements show that 3 40 stations from the PVC, the vertical curve offset is 3.5ft. Assess the adequacy of this existing curve in light of the reconstruction design speed of 60mph and, if the existing curve is inadequate, compute a satisfactory curve length.

Engineering
1 answer:
CaHeK987 [17]3 years ago
8 0

Answer:

The provided length of the vertical curve is satisfactory for the reconstruction design speed of 60 mi/h

Explanation:

The explanation is shown on the first uploaded image

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A flywheel performs each of these functions except: A. Contains a gear used for engine starting B. Smoothes engine operation C.
torisob [31]

Answer:

C. Provides lubrication to parts

Explanation:

Flywheel :

 Flywheel is a device which stored the mechanical energy.This energy can be use when more energy required during any operation.Due to high moment of inertia of the flywheel it resist the change in the speed .The flywheel is attached to the crank shaft at the rear side of the engine.

The flywheel perform following function:

1. It connects the crankshaft and the transmission system.

2.It makes the engine operation smooth.

3.It contains gear and other parts of the engine.

But it can not provide lubrication.

C. Provides lubrication to parts

4 0
3 years ago
The cold drawn AISI 1040 steel bar with 25-mm width and 10-mm thick has a 6- mm diameter thru hole in the center of the plate. T
4vir4ik [10]

Answer:

A)  ( N ) = 1.54

B)  N ( Goodman ) = 1.133,  N ( Morrow) = 1.35

Explanation:

width of steel bar = 25-mm

thickness of steel bar = 10-mm

diameter = 6-mm

load on plate = between 12 kN AND 28 kN

notch sensitivity = 0.83

A ) Fatigue factor of safety based on yielding criteria

= δa + δm = \frac{Syt}{n}   =  91.03 + 227.58 = 490 / N

therefore Fatigue number of safety ( N ) = 1.54

δa (amplitude stress ) = kf ( Fa/A) = 2.162 * ( 8*10^3 / 190 ) = 91.03 MPa

A = area of steel bar = 190 mm^2 , Fa = amplitude load = 8 KN , kf = 2.162

δm (mean stress ) = kf ( Fm/A ) = (2.162 * 20*10^3 )/ 190 = 227.58 MPa

Fm = mean load  = 20 *10^3

B) Fatigue factor of safety based on Goodman and Morrow criteria

δa / Se + δm / Sut = 1 / N

= 91.03 / 183.15 + 227.58 / 590 = 1 /N

Hence N = 1.133 ( based on Goodman criteria )

note : Se = endurance limit (calculated) = 183.15 , Sut = 590

applying Morrow criteria

N =   1 / ( δa/Se) + (δm/ δf )

   = 1 / ( 91.03 / 183.15 ) + (227.58 / 935 )  

   = 1.35

6 0
3 years ago
17
timofeeve [1]
A. The factor by which a machine multiplies a force
6 0
3 years ago
A closed system consisting of 4 lb of a gas undergoes a process during which the relation between pressure and volume is pVn 5 c
gayaneshka [121]

Answer:

V1=5<u>ft3</u>

<u>V2=2ft3</u>

n=1.377

Explanation:

PART A:

the volume of each state is obtained by multiplying the mass by the specific volume in each state

V=volume

v=especific volume

m=mass

V=mv

state 1

V1=m.v1

V1=4lb*1.25ft3/lb=5<u>ft3</u>

state 2

V2=m.v2

V2=4lb*0.5ft3/lb=  <u> 2ft3</u>

PART B:

since the PV ^ n is constant we can equal the equations of state 1 and state 2

P1V1^n=P2V2^n

P1/P2=(V2/V1)^n

ln(P1/P2)=n . ln (V2/V1)

n=ln(P1/P2)/ ln (V2/V1)

n=ln(15/53)/ ln (2/5)

n=1.377

3 0
3 years ago
The corner store sells candy in ₵20, ₵30 and ₵50 packages. List all the ways in which the Candyman
Novosadov [1.4K]

Answer: I will list them down below!

Explanation:

He can buy 6, 50 cent candies.

He can buy 30, 20 cent candies.

He can buy 6, 30 cent candies and 6, 20 cent candies.

He can buy 15, 20 cent candies and 3, 50 cent candies.

He can by 3, 20 and 30 cent candies and 3, 50 cent candies.

That's it.

Hope this helps!

6 0
1 year ago
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