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allsm [11]
3 years ago
14

A highway reconstruction project is being undertaken to reduce crash rates. The reconstruction involves a major realignment of t

he highway such that a 60mph design speed is attained. At one point on the highway, a 720-ft equal tangent crest vertical curve exists. Measurements show that 3 40 stations from the PVC, the vertical curve offset is 3.5ft. Assess the adequacy of this existing curve in light of the reconstruction design speed of 60mph and, if the existing curve is inadequate, compute a satisfactory curve length.

Engineering
1 answer:
CaHeK987 [17]3 years ago
8 0

Answer:

The provided length of the vertical curve is satisfactory for the reconstruction design speed of 60 mi/h

Explanation:

The explanation is shown on the first uploaded image

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The arrival rate at a parking lot is 6 veh.min. Vehicles start arriving at 6:00PM and when the queue reaches 36 vehicles, servic
seraphim [82]

Answer:

Departure rate = 7.65 vehicle/min

Explanation:

See the attached file for the calculation.

5 0
3 years ago
A piston–cylinder assembly contains 5 kg of air, initially at 2.0 bar, 30 C. The air undergoes a process to a state where the pr
Ainat [17]

Answer: wor done is 145. 06kJ

Heat transfer is 135.53kJ

Explanation:

No of moles of air = mass/molar mass = 5000g/28gmol^-1 = 172.65mol

P1 = 2bar =2*101300 =202600pa

T1 = 30° +273k = 303k

P2 =p1 = 202600pa

V2 =? T2 =?

Using pV = nRT

R = 8.314 PA m^3 mol^-1 k^-1

V1 = (172.65*8.314*303)/202600

V1 = 2.146m^3

For second state, 1.5pv = const = P1V1

V2 = (202600*2.146)/(1.5*202600)

V2 = 1.43m^3

Volume change = 2.146 - 1.43 =0.715m^3

Word done = pressure* volume change

W = 202600*0.716 = 145061.6J

= 145.061kJ

Using V1/T1 = V2/T2

T2 = V2T1/V1

=(1.43*303)/2.146 = 201.9k

For internal energy U

U = nCv*(T2 - T1)

*CV is the heat capacity at const. vol approximately 0.718J mol^-1 k^-1

U = 172.65*0.718*(201.9-303)

U = -12532.6J = -12.532kJ

The -ve means the system lost internal energy.

Q = U+W = total heat energy of system

Q = - 12.532+145.061 = 132.52 kJ

7 0
4 years ago
Florida's progressive DUI laws take ______<br> into account.
xz_007 [3.2K]

Answer:

Permanent felony conviction on your criminal record.

Financial restitution if DUI involves an accident, property damage or personal injury

Up to 50 hours community service or fee of $10 per hour of service.

Minimum fine of upto $1000 or $2000, that is if your blood alcohol level was 0.15%  or more than this, or you were driving with a minor in the vehicle.

Imprisonment of upto 9 months, if the blood alcohol level was over 0.15% or idf the DUI  resulted in ana accident or crash, jail time is increased to one year.

Mandatory imprisonment for not less than 10 days if your second DUI conviction occurs within 5 years of the date of the prior DUI conviction.

180 days to one year probation.

Maximum of 5 years driver's license revocation.

Up to 30 days impoundment of vehicle.

Ignition interlock device.

Criminal record stating adjudication of guilt.

Explanation:

8 0
3 years ago
Draw a 3-D physical structure of an NMOS transistor. Label four terminals: body, drain, gate, and source. And also label silicon
Vanyuwa [196]

Answer:

Answer is attached.

Explanation:

A NMOS is a n-channel MOSFET or Metal Oxide

Semiconductor Field Effect Transistor. This type

of transistor might be an enhancement or

depletion type nMOS transistor designed using

layers of Metal-oxide, Silicon-oxide and Silicon

fabricated on a substrate.

4 0
3 years ago
Poles are values of Laplace transform variable, s, that make denominator of transfer function zero. Zeros are values of Laplace
Ostrovityanka [42]

Answer:

Zero 1 = -1

Zero 2 = -3

Pole 1 = 0

Pole 2 = -2

Pole 3 = -4

Pole 4 = -6

Gain = 4

Explanation:

For any given transfer function, the general form is given as

T.F = k [N(s)] ÷ [D(s)]

where k = gain of the transfer function

N(s) is the numerator polynomial of the transfer function whose roots are the zeros of the transfer function.

D(s) is the denominator polynomial of the transfer function whose roots are the poles of the transfer function.

k [N(s)] = 4s² + 16s + 12 = 4[s² + 4s + 3]

it is evident that

Gain = k = 4

N(s) = (s² + 4s + 3) = (s² + s + 3s + 3)

= s(s + 1) + 3 (s + 1) = (s + 1)(s + 3)

The zeros are -1 and -3

D(s) = s⁴ + 12s³ + 44s² + 48s

= s(s³ + 12s² + 44s + 48)

= s(s + 2)(s + 4)(s + 6)

The roots are then, 0, -2, -4 and -6.

Hope this Helps!!!

3 0
4 years ago
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