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allsm [11]
3 years ago
14

A highway reconstruction project is being undertaken to reduce crash rates. The reconstruction involves a major realignment of t

he highway such that a 60mph design speed is attained. At one point on the highway, a 720-ft equal tangent crest vertical curve exists. Measurements show that 3 40 stations from the PVC, the vertical curve offset is 3.5ft. Assess the adequacy of this existing curve in light of the reconstruction design speed of 60mph and, if the existing curve is inadequate, compute a satisfactory curve length.

Engineering
1 answer:
CaHeK987 [17]3 years ago
8 0

Answer:

The provided length of the vertical curve is satisfactory for the reconstruction design speed of 60 mi/h

Explanation:

The explanation is shown on the first uploaded image

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In a right triangle, the square of the length of one side is equal to the sum of the squares of the lengths of the other two sid
Dovator [93]

Answer:

C++ code is explained below

Explanation:

/Remove the following line

//if not using visual studio.

#include "stdafx.h"

//Import the required header files.

#include <iostream>

using namespace std;

//Define the main function.

int main(void)

{

    //Define the variables.

    double side1, side2, side3;

    //Prompt the user to enter the sides of the triangle.

    cout << "Enter the side of the triangle:" << endl;

    cout << "Enter first side of triangle:" << endl;

    cin >> side1;

    cout << "Enter second side of triangle:" << endl;

    cin >> side2;

    cout << "Enter third side of triangle:" << endl;

    cin >> side3;

    cout << endl;

    //Check if the triangle sides are valid

    if ((side1 + side2 > side3) &&

         (side1 + side3 > side2) &&

         (side2 + side3 > side1))

    {

         //Check the condition for right angle triangle

         if ((side3*side3 == (side1*side1 + side2*side2)) ||

             (side2*side2 == (side3*side3 + side1*side1)) ||

             (side1*side1 == (side3*side3 + side2*side2)))

//Display that the triangle is right-angled triangle.

             cout << "It is a right-angled triangle." << endl;

         else

//Display that the triangle is not the right-//angled triangle.

             cout << "It is not a right-angled triangle."

<< endl;

    }

    else

         //Display not the valid side.

         cout << "Not a valid side." << endl;

    //Remove the following line if

    //not using visual studio.

    system("pause");

    return 0;

}

8 0
2 years ago
Two mass streams of the same ideal gas are mixed in a steady-flow chamber while receiving energy by heat transfer from the surro
loris [4]

Answer:

(a)The final temperature of mixture is T₃ =m₁T₁/m₃+ m₂T₂/m₃ + Qin/m₃Cp

(b) The final volume is V₃ =V₁ + V₂ + RQin/P₃Cp

(c) The volume flow rate at exit is V₃ =V₁ + V₂

Explanation:

Solution

Now

The system comprises of two inlets and on exit.

Mass flow rate enthalpy of fluid from inlet -1 be m₁ and h₁

Mass flow rate enthalpy of fluid from inlet -2 be m₂ and h₂

Mass flow rate enthalpy of fluid from  exit be m₃ and h₃

Mixing chambers do not include any kind of work (w = 0)

So, both  the kinetic and potential energies of the fluid streams are usually negligible (ke =0, pe =0)

(a) Applying the mass balance of mixing chamber, min = mout

Applying the energy balance of mixing chamber,

Ein = Eout

min hin =mout hout

miCpT₁ + m₂CpT₂ +Qin =m₃CpT₃

T₃ = miCpT₁/m₃CpT₃ + m₂CpT₂/m₃CpT₃ + Qin/m₃CpT₃ +

T₃ =m₁T₁/m₃+ m₂T/m₃ + Qin/m₃Cp

The final temperature of mixture is T₃ =m₁T₁/m₃+ m₂T₂/m₃ + Qin/m₃Cp

(b) From the ideal gas equation,

v =RT/PT

v₃ = RT₃/P₃

The volume flow rate at the exit, V₃ =m₃v₃

V₃ = m₃ RT₃/P₃

Substituting the value of T₃, we have

V₃=m₃ R/P₃ (=m₁T₁/m₃+ m₂T₂/m₃ + Qin/m₃Cp)

V₃ =  R/P₃ (m₁T₁+ m₂T₂ + Qin/Cp)

Now

The mixing process occurs at constant pressure P₃=P₂=P₁.

Hence V₃ becomes:

V₃=m₁RT₁/P₁ +m₂RT₂/P₂ + RQin/P₃Cp

V₃ =V₁ + V₂ + RQin/P₃Cp

Therefore, the final volume is V₃ =V₁ + V₂ + RQin/P₃Cp

(c) Now for an adiabatic mixing, Qin =0

Hence V₃ becomes:

V₃ =V₁ + V₂ + r * 0/P₃Cp

V₃ =V₁ + V₂ + 0

V₃ =V₁ + V₂

Therefore the volume flow rate at exit is V₃ =V₁ + V₂

8 0
3 years ago
Explain the two advantages and the two disadvantages of fission as an energy source.
yawa3891 [41]

Answer with Explanation:

1) The advantages of fission energy are:

a) Higher concentration of energy : Concentration of energy or the energy density is defined as the amount of energy that is produced by burning a unit mass of the fuel. The nuclear energy obtained by fission has the highest energy density among all the other natural sources of energy such as coal,gas,e.t.c.

b) Cheap source of energy : The cost at which the energy is produced by a nuclear reactor after it is operational is the lowest among all the other sources of energy such as coal, solar,e.t.c

2) The disadvantages of fission energy are:

a) Highly dangerous residue: The fuel that is left unspent is highly radioactive and thus is very dangerous. Usually the residual material is taken deep into the earth for it's disposal.

b) It has high initial costs of design and development: The cost to design a nuclear reactor and to built one after it is designed is the most among all other types of energy sources and requires highly skilled personnel for operation.

6 0
2 years ago
For the following gear train, if the blue gear is moving at 50 rpm, what are the speeds of the other gears?
Flauer [41]

Answer:

6

Explanation:

6 teddy bears

5 0
3 years ago
An experiment to determine the convection coefficient associated with airflow over the surface of a thick stainless steel castin
Maksim231197 [3]

Answer:

h = 375 KW/m^2K

Explanation:

Given:

Thermo-couple distances: L_1 = 10 mm , L_2 = 20 mm

steel thermal conductivity k = 15 W / mK

Thermo-couple temperature measurements: T_1 = 50 C , T_2 = 40 C

Air Temp T_∞ = 100 C

Assuming there are no other energy sources, energy balance equation is:

                                               E_in = E_out

                                        q"_cond = q"_conv

Since, its a case 1-D steady state conduction, the total heat transfer rate can be found from Fourier's Law for surfaces 1 and 2

q"_cond = k * (T_1 - T_2) / (L_2 - L_1) = 15 * (50 - 40) / (0.02 - 0.01)

=15KW/m^2

Assuming SS is solid, temperature at the surface exposed to air will be 60 C since its gradient is linear in the case of conduction, and there are two temperatures given in the problem. Convection coefficient can be found from Newton's Law of cooling:

q"_conv = h * ( T_∞  - T_s ) ----> h = q"_conv / ( T_∞  - T_s )

                                                   h = 15000 W / (100 - 60 ) C = 375 KW/m^2K

4 0
2 years ago
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