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Kaylis [27]
3 years ago
6

A certain piece of property is assessed at $150,000. If the tax rate is $2.50 per $100, what is the tax on this property?

Engineering
1 answer:
stiks02 [169]3 years ago
7 0

Answer:

The tax on this property is 3750 dollars

Explanation:

Given

Tax on per $100 is $2.50

Tax on every $1 is \frac{2.5}{100} = 0.025 dollars

Tax on property of value $150,000 is

150,000 * 0.025 = 3750 dollars

The tax on this property is 3750 dollars

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A car engine with a thermal efficiency of 33% drives the air-conditioner unit (a refrigerator) besides powering the car and othe
fgiga [73]

Answer:

The rate of fuel required to drive the air conditioner Q_h = 6.061 kW

The flow rate of the cold air is  \r m = 0.30765 kg/s

Explanation:

From this question we are told that

    The efficiency is \eta = 33% = 0.33

   Temperature for the hot day is  T_h = 35^oC = 308 K \  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (35+273)

        Temperature after cooling is  T_c = 5^oC = 278K

      The input power is  P_{in} = 2kW

The rate of fuel required to drive the air conditioner can be mathematically represented as

              Q_h = \frac{P_{in}}{\eta}

                    = \frac{2}{0.33} = 6.061 kW

From the question the air condition is assumed to be half as a Carnot refrigeration unit

 This can be Mathematically interpreted in terms of COP(coefficient of performance) as

             \beta_{air} = 0.5 \beta

where \beta  denotes COP and is mathematically represented as

                     \beta = \frac{Q_c}{P_{in}}

= >              Q_c = \beta P_{in}

Where Q_c is the rate of flue being burned for cold air to flow

Now if  the COP of a Carnot refrigerator is having this value

                \beta_{Carnot } = \frac{T_c}{T_h - T_c}

                            = \frac{278}{308-278}

                            \beta_{Carnot} = 9.267\\

Then

     \beta_{air} = 0.5 * 9.2667

            = 4.6333

Now substituting the value of \beta to solve for Q_c

                             Q_c = \beta P_{in}

                                  = 4.6333 *2

                                  9.2667kW

The equation for the rate of fuel being burned for the cold air to flow

                       Q_c = \r mc_p \Delta T

Making the flow rate of the cold air

                       \r m = \frac{Q_c}{c_p \Delta T}

                            = \frac{9.2667}{1.004}* (308 - 278)

                            = 0.30765 kg/s

                         

                             

4 0
3 years ago
C+ Write a program that converts degrees Fahrenheit to Celsius using the following formula. degreesC = 5(degreesF – 32)/9
Yanka [14]

Answer:

Written in C++

#include<iostream>

#include<cmath>

using namespace std;

int main()

{

float degreeC, degreeF;

cout<<"Degree Fahrenheit: ";

cin>>degreeF;

degreeC = 5 * (degreeF - 32)/9;

cout<<"Degree Celsius: "<<degreeC<<" C";  

return 0;

}

Explanation:

The question requests that input should be in degree Fahrenheit

Declare all necessary variables

float degreeC, degreeF;

Prompt user for input in degrees Fahrenheit as stated in the question

cout<<"Degree Fahrenheit: ";

Get User Input

cin>>degreeF;

Convert degree Fahrenheit to Celsius

degreeC = 5 * (degreeF - 32)/9;

Display output

cout<<"Degree Celsius: "<<degreeC<<" C";  

4 0
3 years ago
A cylinder 8 in. in diameter and 3 ft long is concentric with a pipe of 8.25 in internal diameter. Between the cylinder and the
yarga [219]

Answer:

What force is requiere to move the cylinder along

Explanation:

The kinematic viscosity of the ol is 0.006 fr2

5 0
3 years ago
A specimen of copper having a rectangular cross section 15.2 mm × 19.1 mm (0.60 in. × 0.75 in.) is pulled in tension with 44,500
lukranit [14]

Answer:

The resulting strain is 1.39\times 10^{-3}.

Explanation:

A specimen of copper having a rectangular cross section 15.2 mm × 19.1 mm

Force, F = 44,500 N

Th elastic modulus of Cu to be 110 GPa

The resulting strain is given by the formula as follows :

\epsilon=\dfrac{F}{AE}

E is elastic modulus of Cu is are of cross section

\epsilon=\dfrac{44500}{15.2\times 19.1\times 10^{-6}\times 110\times 10^9}\\\\\epsilon=1.39\times 10^{-3}

So, the resulting strain is 1.39\times 10^{-3}.

6 0
4 years ago
1.identify two major inventions or innovations related to each engineering and technology pathway
Arte-miy333 [17]

Explanation:

Things related to engineering:

- Electric Motor

- Combustion Engine

Hope this helped!

7 0
3 years ago
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