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3 years ago

I don’t know the answer PLEASE HELP ME right answers only

Mathematics

1 answer:

Zepler [3.9K]3 years ago

4 0

B lemniscate for that question

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-4x-1+4x=3 solve for x

soldier1979 [14.2K]

Answer:

-14x-1+4x=3

Step-by-step explanation:

it's all in the pic

7 0

3 years ago

Which two city parks have equivalent ratios of planted maple trees to the total number of trees in the park?

lana [24]

Answer:

Eastern and west end

Step-by-step explanation:

divide by nine

6 0

3 years ago

Read 2 more answers

Please prove this........

Crazy boy [7]

Answer: see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π → C = π - (A + B)

→ sin C = sin(π - (A + B)) cos C = sin(π - (A + B))

→ sin C = sin (A + B) cos C = - cos(A + B)

Use the following Sum to Product Identity:

sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]

cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]

Use the following Double Angle Identity:

sin 2A = 2 sin A · cos A

<u>Proof LHS → RHS</u>

LHS: (sin 2A + sin 2B) + sin 2C

$\text{Sum to Product:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-\sin 2C$

$\text{Double Angle:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-2\sin C\cdot \cos C$

$\text{Simplify:}\qquad \qquad 2\sin (A + B)\cdot \cos (A - B)-2\sin C\cdot \cos C$

$\text{Given:}\qquad \qquad \quad 2\sin C\cdot \cos (A - B)+2\sin C\cdot \cos (A+B)$

$\text{Factor:}\qquad \qquad \qquad 2\sin C\cdot [\cos (A-B)+\cos (A+B)]$

$\text{Sum to Product:}\qquad 2\sin C\cdot 2\cos A\cdot \cos B$

$\text{Simplify:}\qquad \qquad 4\cos A\cdot \cos B \cdot \sin C$

LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C $\checkmark$

7 0

4 years ago

Which value of n makes this equation true?

Vitek1552 [10]

Answer:

wdwd

Step-by-step explanation:

4 0

3 years ago

For the given piecewise function, evaluate for the specified value of x

Gennadij [26K]

Answer:

-1

Step-by-step explanation:

For piecewise functions, you should look at the range of values and see where the number you are looking for falls. In this case, -1 is included in the domain of the middle equation, so you will be using f(x) = x

Then, all you have to do is plug in -1 for x, so f(-1) = -1

6 0

3 years ago