Answer:
Gage pressure at the bottom of the tank = 46.1kP
Explanation:
Note that it is required to expressed the gage pressure ,pressure at the free surface=0 gage
Pressure due to the oil layer= (3m)*((800kg/m^3)(9.81m/s^2))/1000=25.9kpa
Pressure due to the brine layer=(2m)*((1030kg/m^3)(9.81m/s^2))/1000=20.2ka
Therefore, the pressure at the bottom=25.9+20.2=46.1kP
Answer:
A rivet is a mechanical fastener composed of a head on one end and a cylindrical stem on another (called the tail) which has the appearance of a metal pin.
When installed the rivet is either drilled, placed or punched into a hole, afterwards the tail is then deformed, holding the rivet in place. When finished the tail has the appearance of a dumbbell shape completing the riveted joint.
To solve the problem it is necessary to use the concepts related to frictional dissipation per unit mass, energy balance equation and Volumetric flow rate.
The frictional dissipation per unit mass is defined as
Where,
Superficial velocity of fluid
Fluid viscoisty
Porosity
Fluid density
L = Packed bed length
= Effective particle diameter
Through energy balance equation we have that
Neglect the change in velocity and pressure and the work done we have,
We have also that de grade is defined as
With our values and replacing at the previous equation we have,
Previously with the given depth and height we have to
Therefore the Volumetric flow rate,
Therefore the desired volumetric flow rate is 2456gal/min