Answer:
(a). the resultant force in the direction of the freestream velocity is termed the drag and the resultant force normal to the freestream velocity is termed the lift
Explanation:
When a fluid flows around the surface of an object, it exerts a force on it. This force has two components, namely lift and drag.
The component of this force that is perpendicular (normal) to the freestream velocity is known as lift, while the component of this force that is parallel or in the direction of the fluid freestream flow is known as drag.
Lift is as a result of pressure differences, while drag results from forces due to pressure distributions over the object surface, and forces due to skin friction or viscous force.
Thus, drag results from the combination of pressure and viscous forces while lift results only from the<em> pressure differences</em> (not pressure forces as was used in option D).
The only correct option left is "A"
(a). the resultant force in the direction of the freestream velocity is termed the drag and the resultant force normal to the freestream velocity is termed the lift
Answer:
0.287
Explanation:
Design-stage uncertainty can be expressed as :
Ud = √ Uo^2 + Uc^2 ------ ( 1 )
where : Uo = 1/2( resolution value ) = 1/2 * 0.01 V = 0.005 V
Uc = √(0.10)^2 + (0.10)^2 + (0.15)^2 + (0.20)^2 = 0.287
back to equation 1
Ud = √ ( 0.005)^2 + ( 0.287 )^2 = 0.287
Answer:
0.0833 k J/k
Explanation:
Given data in question
total amount of heat transfedded (Q) = 100 KJ
hot reservoir temperature R(h) = 1200 K
cold reservoir temperature R(c) = 600 k
Solution
we will apply here change of entropy (Δs) formula
Δs = 
Δs = 
Δs = 
Δs = 0.0833 K J/k
this change of entropy Δs is positive so we can say it is feasible and
increase of entropy principle is satisfied
Answer:
The plot of the function production rate m(t) (in kg/min) against time t (in min) is attached to this answer.
The production rate function M(t) is:
![m(t)=[H(t)\cdot10+H(t-20)\cdot5-H(t-80)\cdot14+H(t-81)\cdot9]kg/min](https://tex.z-dn.net/?f=m%28t%29%3D%5BH%28t%29%5Ccdot10%2BH%28t-20%29%5Ccdot5-H%28t-80%29%5Ccdot14%2BH%28t-81%29%5Ccdot9%5Dkg%2Fmin)
(1)
The Laplace transform of this function is:
![\displaystyle m(s)=[\frac{10+5e^{-20s}-14e^{-80s}+9e^{-81s}}{s}]kg/min](https://tex.z-dn.net/?f=%5Cdisplaystyle%20m%28s%29%3D%5B%5Cfrac%7B10%2B5e%5E%7B-20s%7D-14e%5E%7B-80s%7D%2B9e%5E%7B-81s%7D%7D%7Bs%7D%5Dkg%2Fmin)
(2)
Explanation:
The function of the production rate can be considered as constant functions by parts in the domain of time. To make it a continuous function, we can use the function Heaviside (as seen in equation (1)). To join all the constant functions, we consider at which time the step for each one of them appears and sum each function multiply by the function Heaviside.
For the Laplace transform we use the following rules:
![\mathcal{L}[f(x)+g(x)]=\mathcal{L}[f(x)]+\mathcal{L}[g(x)]=F(s)+G(s)](https://tex.z-dn.net/?f=%5Cmathcal%7BL%7D%5Bf%28x%29%2Bg%28x%29%5D%3D%5Cmathcal%7BL%7D%5Bf%28x%29%5D%2B%5Cmathcal%7BL%7D%5Bg%28x%29%5D%3DF%28s%29%2BG%28s%29)
(3)
![\mathcal{L}[aH(x-b)]=\displaystyle\frac{ae^{-bs}}{s}](https://tex.z-dn.net/?f=%5Cmathcal%7BL%7D%5BaH%28x-b%29%5D%3D%5Cdisplaystyle%5Cfrac%7Bae%5E%7B-bs%7D%7D%7Bs%7D)
(4)
Answer:
perpetual motion machine of second type is a machine that generates job from a single source of heat.
Explanation:
perpetual motion machine is a machine that generates job from a single source of heat. only one heat reservoir is present in this type of machine and it is continuously cooled to generate function without transferring heat to a cooler reservoir. Such a demonstration machine was names as ammonia engine
