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Komok [63]
3 years ago
13

When fermentation units are operated with high aeration rates, significant amounts of water can be evaporated into the air passi

ng through the fermentation broth. Since fermentation can be adversely affected if water loss is significant, the air is humidified before being fed to the fermenter. Sterilized ambient air is combined with steam to form a saturated air–water mixture at 1 atm and 90°C. The mixture is cooled to the temperature of the fermenter (35°C), condensing some of the water, and the saturated air is fed to the bottom of the fermenter. For an air flow rate to the fermenter of 10 L/min at 35°C and 1 atm, estimate the rate at which steam must be added to the sterilized air and the rate (kg/min) at which condensate is collected upon cooling the air–steam mixture.

Engineering
1 answer:
guapka [62]3 years ago
5 0

Answer and Explanation:

The answer is attached below

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What is a core self-evaluation, include identifying and explaining the components of core self-evaluation. And, how a group lead
Brilliant_brown [7]

Answer and Explanation:

Core self-evaluations (CSEs) stands for a wide personality trait that comprises of 4 positive individual traits, namely:

(1) self-efficacy

(2) self esteem

(3) locus of control

(4) emotional stability.

Baiscally, when people have a positive evaluation about themselves, or quality core self-evaluation, they believe that they are worthy and fit for a task. They trust their capability and effectiveness. This leads to some implications in their managers duties and careers, which could either be positive or negative.

A group leader can use CSEs to create a more effective unit by implementing the ten items points of Generalized Self Efficacy Tool to test the self efficiency of individual personnels in that unit.

8 0
3 years ago
Read 2 more answers
Describe what V1-V4 is
photoshop1234 [79]

Answer:

it is wave inversion

Explanation:

8 0
3 years ago
What is the maximal coefficient of performance of a refrigerator which cools down 10 kg of water (and then ice) to -6C. Upper he
inysia [295]

Given:

Temperature of water, T_{1} = -6^{\circ}C =273 +(-6) =267 K

Temperature surrounding refrigerator, T_{2} = 21^{\circ}C =273 + 21 =294 K

Specific heat given for water, C_{w} = 4.19 KJ/kg/K

Specific heat given for ice, C_{ice} = 2.1 KJ/kg/K

Latent heat of fusion,  L_{fusion} = 335KJ/kg

Solution:

Coefficient of Performance (COP) for refrigerator is given by:

Max COP_{refrigerator} = \frac{T_{2}}{T_{2} - T_{1}}

= \frac{267}{294 - 267} = 9.89

Coefficient of Performance (COP) for heat pump is given by:

Max COP_{heat pump} = \frac{T_{1}}{T_{2} - T_{1}}\frac{294}{294 - 267} = 10.89

6 0
3 years ago
How can we calculate the speed of the output gear in a simple gear train? Explain with the help of an example.
Snowcat [4.5K]

Answer:

N_3=\dfrac{T_1}{T_3}N_1

Explanation:

In the diagram there three gears in which gear 1 is input gear ,gear 2 is idle gear and gear 3 is out put gear.

Lets take

Speed\ of\ gear 1=N_1

Number\ of\ teeth\ of\ gear 1=T_1

Speed\ of\ gear 3=N_3

Number\ of\ teeth\ of\ gear 3=T_3

All external matting gears will rotates in opposite direction with respect to each other.

So the speed of gear third can be given as follows

\dfrac{T_1}{T_3}=\dfrac{N_3}{N_1}

N_3=\dfrac{T_1}{T_3}N_1

3 0
3 years ago
2) The switch in the circuit below has been closed a long time. At t=0, it is opened.
saul85 [17]

Answer:

  il(t) = e^(-100t)

Explanation:

The current from the source when the switch is closed is the current through an equivalent load of 15 + 50║50 = 15+25 = 40 ohms. That is, it is 80/40 = 2 amperes. That current is split evenly between the two parallel 50-ohm resistors, so the initial inductor current is 2/2 = 1 ampere.

The time constant is L/R = 0.20/20 = 0.01 seconds. Then the decaying current is described by ...

  il(t) = e^(-t/.01)

  il(t) = e^(-100t) . . . amperes

8 0
3 years ago
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