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Alinara [238K]
3 years ago
11

An incandescent light bulb can be regarded as a resistor. If its power output is 100W, calculate the resistance of the light bul

b and the current drawn by the light bulb, assuming the voltage of the power source is 110V.
Engineering
1 answer:
stira [4]3 years ago
8 0

Answer:121\ \Omega

0.909\ A

Explanation:

Given

Power P=100\ W

Voltage applied V=110\ V

Resistance of the bulb is given by

P=\frac{V^2}{R}

100=\frac{110^2}{R}

R=\frac{12100}{100}

R=121\ \Omega

Current drawn by the Power source is given by

P=V\cdot I

I=\frac{P}{V}

I=\frac{100}{110}

I=0.909\ A

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