C hope this helped :-) :-) :-) :-)
Answer: 94 child tickets
<u>Step-by-step explanation:</u>
Let x represent child tickets
Let y represent adult tickets
Cost Equation: 5.70x + 9.75y = 1306.10
Quantity Equation: x + y = 173
Solve the system of equations using the elimination method:
Multiply the Quantity Equation by -5.70
5.70x + 9.75y = 1306.10
<u> -5.70x - 5.70y</u> = <u>-986.10</u>
4.05y = 320.00
<u> ÷4.05 </u> <u>÷4.05 </u>
y = 79
x + y = 173
x + 79 = 173
x = 94
The rate of the wind is given to be 210 the rate of the plane in mid air is given as 830
<h3>Howe to solve for the rate of the plane and wind</h3>
In 7 hours the kilometer traveled = 4340
P + W = 4340/7
= 620
P-W = 3120/3 hours
= 1040
2p = 1040 + 620
= 1660
p =830
W = 1040 - 830
= 210
Hence the rate of the wind is given to be 210 the rate of the plane in mid air is given as 830
Read more on rate here
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Answer:
10.77 units
Step-by-step explanation:
By imaging an imaginery line at point before 1 units to be 4 units: b = 4 units
Therefore h = 11 - 1 = 10 units
Using Pythagoras theorem:
x² = h² + b² = 10² + 4² = 100 + 16 = 116
x = √116 = 10.77 units
Answer:
part A: expression 1: 6(8m+2)
expression 2: 6m+12+42m
Part B: 6(m+2+7m)= 6(8m+2)
combine like terms is 6(m+2+7m), so it is 6(2+8m) or 6(8m+2)
6(8m+2)= 6(8m+2)
Part C: 6m+12+42m=6(m+2+7m)
m=0
6(0+2+7(0))=6(0)+12+42(0)
6(2)= 12
12=12
